I have an array in PHP, which looks like this:
我有一个PHP数组,看起来像这样:
array (
[0] => array (
[id] => 1
[title] => "Title 1"
[parent_id] => NULL
[depth] => 0
)
[1] => array (
[id] => 2
[title] => "Title 2"
[parent_id] => NULL
[depth] => 0
)
[2] => array (
[id] => 3
[title] => "Title 3"
[parent_id] => 2
[depth] => 1
)
[3] => array (
[id] => 4
[title] => "Title 4"
[parent_id] => 2
[depth] => 1
)
[4] => array (
[id] => 5
[title] => "Title 5"
[parent_id] => NULL
[depth] => 0
)
[5] => array (
[id] => 6
[title] => "Title 6"
[parent_id] => 4
[depth] => 2
)
)
What i want to do is iterate over this array and create a nested <ol>
list from it. So the result should look like this:
我想要做的是迭代这个数组并从中创建一个嵌套的
-
列表。所以结果应该是这样的:
<ol>
<li>Title 1</li> // id = 1
<li>Title 2</li> // id = 2
<ol>
<li>Title 3</li> // id = 3 -> parent_id = 2
<li>Title 4</li> // id = 4 -> parent_id = 2
<ol>
<li>Title 6</li> // id = 6 -> parent_id = 4
</ol>
</ol>
<li>Title 5</li> // id = 5
</ol>
I've been trying to think of a way how i could get this done. But so far every attempt failed...
我一直试图想办法如何完成这项工作。但到目前为止每次尝试都失败了
Anyone any idea how i can create such a nested <ol>
list from an array like that?
任何人都知道如何从这样的数组创建这样一个嵌套的
-
列表?
Please note that i do not have any control on the given data. I simply make a call to an API and it returns json data, which i convert to an array. And the array looks exactly like the one i described.
请注意,我对给定数据没有任何控制权。我只是调用一个API,它返回json数据,我将其转换为数组。阵列看起来与我描述的完全一样。
3 个解决方案
#1
13
You should use recursion:
你应该使用递归:
First the array in 'php' syntax:
首先是'php'语法中的数组:
<?php
$a=array (
'0' => array (
'id' => 1,
'title' => "Title 1",
'parent_id' => 'NULL',
'depth' => 0
),
'1' => array (
'id' => 2,
'title' => "Title 2",
'parent_id' => 'NULL',
'depth' => 0
),
'2' => array (
'id' => 3,
'title' => "Title 3",
'parent_id' => 2,
'depth' => 1
),
'3' => array (
'id' => 4,
'title' => "Title 4",
'parent_id' => 2,
'depth' => 1
),
'4' => array (
'id' => 5,
'title' => "Title 5",
'parent_id' => 'NULL',
'depth' => 0
),
'5' => array (
'id' => 6,
'title' => "Title 6",
'parent_id' => 4,
'depth' => 0
)
);
Here the code:
这里的代码:
$level = 'NULL';
function r( $a, $level) {
$r = "<ol>";
foreach ( $a as $i ) {
if ($i['parent_id'] == $level ) {
$r = $r . "<li>" . $i['title'] . r( $a, $i['id'] ) . "</li>";
}
}
$r = $r . "</ol>";
return $r;
}
print r( $a, $level );
?>
The results:
结果:
<ol><li>Title 1<ol></ol></li><li>Title 2<ol><li>Title 3<ol>
</ol></li><li>Title 4<ol><li>Title 6<ol></ol></li></ol></li></ol></li><li>Title 5
<ol></ol></li></ol>
- Title 1\n
- 标题1 \ n
- Title 2\n
- Title 3\n
- 标题3 \ n
- Title 4\n
- Title 6\n
- 标题6 \ n
- Title 6\n
- 标题4 \ n标题6 \ n
- Title 3\n
- 标题2 \ n标题3 \ n标题4 \ n标题6 \ n
- Title 5\n
- 标题5 \ n
EDITED AFTER CHECK AS SOLUTION
检查后作为解决方案编辑
To avoid empty leafs:
为了避免空叶:
function r( $a, $level) {
$r = '' ;
foreach ( $a as $i ) {
if ($i['parent_id'] == $level ) {
$r = $r . "<li>" . $i['title'] . r( $a, $i['id'] ) . "</li>";
}
}
return ($r==''?'':"<ol>". $r . "</ol>");
}
#2
4
You can try the following
您可以尝试以下方法
$array = array (
"0" => array (
"id" => 1,
"title" => "Title 1",
"parent_id" => NULL,
"depth" => 0
),
"1" => array (
"id" => 2,
"title" => "Title 2",
"parent_id" => NULL,
"depth" => 0
),
"2" => array (
"id" => 3,
"title" => "Title 3",
"parent_id" => 2,
"depth" => 1
),
"3" => array (
"id" => 4,
"title" => "Title 4",
"parent_id" => 2,
"depth" => 1
),
"4" => array (
"id" => 5,
"title" => "Title 5",
"parent_id" => NULL,
"depth" => 0
),
"5" => array (
"id" => 6,
"title" => "Title 6",
"parent_id" => 4,
"depth" => 0
)
);
echo(make($array));
Output
产量
<ol>
<li>Title 1</li>
<li>Title 2</li>
<ol>
<li>Title 3</li>
<li>Title 4</li>
<ol>
<li>Title 6</li>
</ol>
</ol>
<li>Title 5</li>
</ol>
Function Used
使用的功能
function make(array $array, $no = 0) {
$child = hasChildren($array, $no);
if (empty($child))
return "";
$content = "<ol>\n";
foreach ( $child as $value ) {
$content .= sprintf("\t<li>%s</li>\n", $value['title']);
$content .= make($array, $value['id']);
}
$content .= "</ol>\n";
return $content;
}
function hasChildren($array, $id) {
return array_filter($array, function ($var) use($id) {
return $var['parent_id'] == $id;
});
}
观看现场演示
#3
1
The following array:
以下数组:
Array
(
[0] => Content
[1] => Array
(
[0] => International
[1] => Array
(
[0] => Mexico
[1] => Array
(
[0] => Tamaulipas
)
[2] => USA
)
)
)
With this function:
有了这个功能:
function r($element) {
foreach ($element as $value) {
if (!is_array($value)) {
echo "<li>";
echo $value;
} else {
echo "<ul>";
r($value);
echo "</li>";
echo "</ul>";
}
}
}
PHP code:
PHP代码:
echo "<ul>";
r($array);
echo "</ul>";
Returns:
返回:
<ul>
<li>Public</li>
<li>User</li>
<li>Content
<ul>
<li>International
<ul>
<li>Mexico
<ul>
<li>Tamaulipas</li>
</ul>
</li>
<li>USA</li>
</ul>
</li>
</ul>
</li>
</ul>
#1
13
You should use recursion:
你应该使用递归:
First the array in 'php' syntax:
首先是'php'语法中的数组:
<?php
$a=array (
'0' => array (
'id' => 1,
'title' => "Title 1",
'parent_id' => 'NULL',
'depth' => 0
),
'1' => array (
'id' => 2,
'title' => "Title 2",
'parent_id' => 'NULL',
'depth' => 0
),
'2' => array (
'id' => 3,
'title' => "Title 3",
'parent_id' => 2,
'depth' => 1
),
'3' => array (
'id' => 4,
'title' => "Title 4",
'parent_id' => 2,
'depth' => 1
),
'4' => array (
'id' => 5,
'title' => "Title 5",
'parent_id' => 'NULL',
'depth' => 0
),
'5' => array (
'id' => 6,
'title' => "Title 6",
'parent_id' => 4,
'depth' => 0
)
);
Here the code:
这里的代码:
$level = 'NULL';
function r( $a, $level) {
$r = "<ol>";
foreach ( $a as $i ) {
if ($i['parent_id'] == $level ) {
$r = $r . "<li>" . $i['title'] . r( $a, $i['id'] ) . "</li>";
}
}
$r = $r . "</ol>";
return $r;
}
print r( $a, $level );
?>
The results:
结果:
<ol><li>Title 1<ol></ol></li><li>Title 2<ol><li>Title 3<ol>
</ol></li><li>Title 4<ol><li>Title 6<ol></ol></li></ol></li></ol></li><li>Title 5
<ol></ol></li></ol>
- Title 1\n
- 标题1 \ n
- Title 2\n
- Title 3\n
- 标题3 \ n
- Title 4\n
- Title 6\n
- 标题6 \ n
- Title 6\n
- 标题4 \ n标题6 \ n
- Title 3\n
- 标题2 \ n标题3 \ n标题4 \ n标题6 \ n
- Title 5\n
- 标题5 \ n
EDITED AFTER CHECK AS SOLUTION
检查后作为解决方案编辑
To avoid empty leafs:
为了避免空叶:
function r( $a, $level) {
$r = '' ;
foreach ( $a as $i ) {
if ($i['parent_id'] == $level ) {
$r = $r . "<li>" . $i['title'] . r( $a, $i['id'] ) . "</li>";
}
}
return ($r==''?'':"<ol>". $r . "</ol>");
}
#2
4
You can try the following
您可以尝试以下方法
$array = array (
"0" => array (
"id" => 1,
"title" => "Title 1",
"parent_id" => NULL,
"depth" => 0
),
"1" => array (
"id" => 2,
"title" => "Title 2",
"parent_id" => NULL,
"depth" => 0
),
"2" => array (
"id" => 3,
"title" => "Title 3",
"parent_id" => 2,
"depth" => 1
),
"3" => array (
"id" => 4,
"title" => "Title 4",
"parent_id" => 2,
"depth" => 1
),
"4" => array (
"id" => 5,
"title" => "Title 5",
"parent_id" => NULL,
"depth" => 0
),
"5" => array (
"id" => 6,
"title" => "Title 6",
"parent_id" => 4,
"depth" => 0
)
);
echo(make($array));
Output
产量
<ol>
<li>Title 1</li>
<li>Title 2</li>
<ol>
<li>Title 3</li>
<li>Title 4</li>
<ol>
<li>Title 6</li>
</ol>
</ol>
<li>Title 5</li>
</ol>
Function Used
使用的功能
function make(array $array, $no = 0) {
$child = hasChildren($array, $no);
if (empty($child))
return "";
$content = "<ol>\n";
foreach ( $child as $value ) {
$content .= sprintf("\t<li>%s</li>\n", $value['title']);
$content .= make($array, $value['id']);
}
$content .= "</ol>\n";
return $content;
}
function hasChildren($array, $id) {
return array_filter($array, function ($var) use($id) {
return $var['parent_id'] == $id;
});
}
观看现场演示
#3
1
The following array:
以下数组:
Array
(
[0] => Content
[1] => Array
(
[0] => International
[1] => Array
(
[0] => Mexico
[1] => Array
(
[0] => Tamaulipas
)
[2] => USA
)
)
)
With this function:
有了这个功能:
function r($element) {
foreach ($element as $value) {
if (!is_array($value)) {
echo "<li>";
echo $value;
} else {
echo "<ul>";
r($value);
echo "</li>";
echo "</ul>";
}
}
}
PHP code:
PHP代码:
echo "<ul>";
r($array);
echo "</ul>";
Returns:
返回:
<ul>
<li>Public</li>
<li>User</li>
<li>Content
<ul>
<li>International
<ul>
<li>Mexico
<ul>
<li>Tamaulipas</li>
</ul>
</li>
<li>USA</li>
</ul>
</li>
</ul>
</li>
</ul>