将列名与DataTables与AJAX数据源一起使用

时间:2022-12-09 14:29:35

I'm trying to upgrade my system to use 1.10 instead of 1.9 of DataTables and I'm trying to find a way to pass back the row contents using a JSON object instead of a list. Specifically instead of passing back data in the format [['data','data','data'],['data','data','data'],etc..] I want to put it in the format [['colA':'data','colB':'data','colC':'data']].

我正在尝试升级我的系统以使用1.10而不是1.9的DataTables,我正在尝试找到一种方法来使用JSON对象而不是列表来传回行内容。具体而言,不是以[['数据','数据','数据'],['数据','数据','数据']等格式传回数据。]我想把它放在格式中[[ '可乐': '数据', 'COLB': '数据', 'COLC': '数据']]。

Right now I've got my AJAX function returning the data in that format and I'm trying to initialize with this code:

现在我有我的AJAX函数返回该格式的数据,我正在尝试使用以下代码进行初始化:

$("table").DataTable({
    "columnDefs": [
        {"name": "wo_status", "title": "wo_status", "targets": 0},
        //repeat for each of my 20 or so fields
    ],
    "serverSide": true,
    "ajax": "url/to/ajax/function"
});

The results are coming back from my AJAX function correctly but DataTables is trying to find an index of 0 in row 0 and failing to find it because my table cells are indexed by their column name instead of a numerical index. Does anyone know how to tell DataTables to use the column names specified in columnDefs (or in some other option I haven't found) instead of numerical indices?

结果正确地从我的AJAX函数返回,但DataTables试图在第0行中找到0的索引并且未能找到它,因为我的表格单元格被列名而不是数字索引索引。有谁知道如何告诉DataTables使用columnDefs(或其他一些我没有找到的选项)中指定的列名而不是数字索引?

3 个解决方案

#1


9  

Use columns.data option to specify property names as shown below:

使用columns.data选项指定属性名称,如下所示:

$("table").DataTable({
    "columns": [
        { "data": "colA", "name": "colA", "title": "colA" },
        { "data": "colB", "name": "colB", "title": "colB" },
        { "data": "colC", "name": "colC", "title": "colC" }
        //repeat for each of my 20 or so fields
    ],
    "serverSide": true,
    "ajax": "url/to/ajax/function"
});

#2


3  

Use forEach in fnServerParams function...

在fnServerParams函数中使用forEach ...

将列名与DataTables与AJAX数据源一起使用

$("table").DataTable({

  "columns": [{
    "data": "colA"
  }, {
    "data": "colB"
  }, {
    "data": "colC"
  }],

  "serverSide": true,

  "ajax": "url/to/ajax/function",

  fnServerParams: function(data) {
      data['order'].forEach(function(items, index) {
          data['order'][index]['column'] = data['columns'][items.column]['data'];
    });
  },
});

#3


0  

Thanks @ahmeti I've updated your approach :)

谢谢@ahmeti我已经更新了你的方法:)

ajax: {
        url: fetchUrl,
        data: function ( data ) {
            data['columns_map'] = {};
            data['columns'].forEach(function(item, index) {
                data['columns_map'][item.data] = data['columns'][index];
            });
            data['order'].forEach(function(item, index) {
                data['order'][index]['column'] = data['columns'][item.column]['data'];
            });
            return {"data": JSON.stringify(data)};
        }
    },

#1


9  

Use columns.data option to specify property names as shown below:

使用columns.data选项指定属性名称,如下所示:

$("table").DataTable({
    "columns": [
        { "data": "colA", "name": "colA", "title": "colA" },
        { "data": "colB", "name": "colB", "title": "colB" },
        { "data": "colC", "name": "colC", "title": "colC" }
        //repeat for each of my 20 or so fields
    ],
    "serverSide": true,
    "ajax": "url/to/ajax/function"
});

#2


3  

Use forEach in fnServerParams function...

在fnServerParams函数中使用forEach ...

将列名与DataTables与AJAX数据源一起使用

$("table").DataTable({

  "columns": [{
    "data": "colA"
  }, {
    "data": "colB"
  }, {
    "data": "colC"
  }],

  "serverSide": true,

  "ajax": "url/to/ajax/function",

  fnServerParams: function(data) {
      data['order'].forEach(function(items, index) {
          data['order'][index]['column'] = data['columns'][items.column]['data'];
    });
  },
});

#3


0  

Thanks @ahmeti I've updated your approach :)

谢谢@ahmeti我已经更新了你的方法:)

ajax: {
        url: fetchUrl,
        data: function ( data ) {
            data['columns_map'] = {};
            data['columns'].forEach(function(item, index) {
                data['columns_map'][item.data] = data['columns'][index];
            });
            data['order'].forEach(function(item, index) {
                data['order'][index]['column'] = data['columns'][item.column]['data'];
            });
            return {"data": JSON.stringify(data)};
        }
    },