求一棵树的镜像树

连接;http://www.nowcoder.com/practice/564f4c26aa584921bc75623e48ca3011?tpId=13&tqId=11171&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking

题目描述

操作给定的二叉树，将其变换为源二叉树的镜像。

输入描述:

二叉树的镜像定义：源二叉树 
        8
       /  \
      6   10
     / \  / \
    5  7 9 11
    镜像二叉树
        8
       /  \
      10   6
     / \  / \
    11 9 7  5

/*
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) :
val(x), left(NULL), right(NULL) {
}
};*/
class Solution {
public:
    void Mirror(TreeNode *pRoot) {
        if(pRoot==NULL) return ;
        Mirror(pRoot->left);
        Mirror(pRoot->right);
        TreeNode* temp=pRoot->left;
        pRoot->left=pRoot->right;
        pRoot->right=temp;
    }
};