剑指Offer(牛客网) 二叉树的镜像

时间:2023-01-21 07:58:20


来源:
​​​ https://www.nowcoder.com/practice/564f4c26aa584921bc75623e48ca3011?tpId=13&tqId=11171&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking​​​ 题目描述
操作给定的二叉树,将其变换为源二叉树的镜像。
输入描述:
二叉树的镜像定义:源二叉树

8
/ \
6 10
/ \ / \
5 7 9 11
镜像二叉树
8
/ \
10 6
/ \ / \
11 9 7 5

//递归

/**
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;

public TreeNode(int val) {
this.val = val;

}

}
*/
public class Solution {
public void Mirror(TreeNode root) {
if(root==null) return ;
Mirror(root.left);//遍历左子树
Mirror(root.right);//遍历右子树
//交换左右节点
TreeNode temp = root.left;
root.left = root.right;
root.right = temp;

}
}