I have the following data.frame:
我有以下data.frame：
> str(trainLabels)
'data.frame': 1000 obs. of 1 variable:
$ V1: int 1 0 0 1 0 1 0 1 1 0 ...
I wish to obtain a factor as follows:
我希望得到如下因素：
> str(trainLabels)
Factor w/ 2 levels "0","1": 1 0 0 1 0 1 0 1 1 0 ...
I have tried:
我努力了：
trainLabels$V1 <- as.factor(trainLabels$V1)
but that doesn't seem to work; it does change the structure, but it's still not what I want.
但这似乎不起作用;它确实改变了结构，但它仍然不是我想要的。
1 个解决方案
#1
1
Instead of reassigning back into the data.frame column,
而不是重新分配回data.frame列，
trainLabels <- as.factor(trainLabels$V1)
Note that in your requirements, the original trainLabels is a data.frame whereas the final output is a vector. They are two completely different objects being assigned to the same name, the latter overwriting the former.
请注意，在您的要求中，原始trainLabels是data.frame，而最终输出是向量。它们是两个完全不同的对象，分配给同一个名称，后者覆盖前者。
#1
1
Instead of reassigning back into the data.frame column,
而不是重新分配回data.frame列，
trainLabels <- as.factor(trainLabels$V1)
Note that in your requirements, the original trainLabels is a data.frame whereas the final output is a vector. They are two completely different objects being assigned to the same name, the latter overwriting the former.
请注意，在您的要求中，原始trainLabels是data.frame，而最终输出是向量。它们是两个完全不同的对象，分配给同一个名称，后者覆盖前者。