I have to import some UTF-8 encoded text-file into my C++Builder 5 program. Are there any components or code samples to accomplish that?
我必须将一些UTF-8编码的文本文件导入到我的C ++ Builder 5程序中。是否有任何组件或代码示例可以实现?
4 个解决方案
#1
You are best off reading all the other questions on SO that are tagged unicode and c++. For starters you should probably look at this one and see whether library in the accepted answer (UTF8-CPP) works for you.
你最好阅读有关标记为unicode和c ++的所有其他问题。对于初学者,你应该看看这个,看看接受的答案(UTF8-CPP)中的库是否适合你。
I would however first think about what you're trying to achieve, as there is no way you can just import UTF-8-encoded strings into "Ansi" (what ever you mean by that, maybe something like ISO8859_1 or WIN1252 encoding?).
然而,我会首先考虑你想要实现的目标,因为你无法将UTF-8编码的字符串导入“Ansi”(你的意思是什么,也许像ISO8859_1或WIN1252编码?) 。
#2
Here is a more VCL-centric approach for you:
这是一个更加以VCL为中心的方法:
UTF8String utf8 = "...";
WideString utf16;
AnsiString latin1;
int len = ::MultiByteToWideChar(CP_UTF8, 0, utf8.c_str(), utf8.Length(), NULL, 0);
utf16.SetLength(len);
::MultiByteToWideChar(CP_UTF8, 0, utf8.c_str(), utf8.Length(), utf16.c_bstr(), len);
len = ::WideCharToMultiByte(1252, 0, utf16.c_bstr(), utf16.Length(), NULL, 0, NULL, NULL);
latin1.SetLength(len);
::WideCharToMultiByte(1252, 0, utf16.c_bstr(), utf16.Length(), latin1.c_str(), len, NULL, NULL);
If you upgrade to CB2009, you can simplify it to this:
如果升级到CB2009,可以将其简化为:
UTF8String utf8 = "...";
AnsiString<1252> latin1 = utf8;
#3
As there is no-one working on weekends, I have to answer it myself :)
由于没有人在周末工作,我必须自己回答:)
String Utf8ToWinLatin1(char* aData, char* aValue)
{
int i=0;
for(int j=0;j<strlen(aData);)
{ int val=aData[j];
int c=(unsigned char)aData[j];
if(c<=127)
{ aValue[i]=c;
j+=1;
i++;
}
else if(c>=192 && c<=223)
{
aValue[i]=(c-192)*64 + (aData[j+1]-128);
i++;
j+=2;
}
else if(c>=224 && c<=239)
{
aValue[i]=( c-224)*4096 + (aData[j+1]-128)*64 + (aData[j+2]-128);
i++;
j+=3;
}
else if(c>=240 && c<=247)
{
aValue[i]=(c-240)*262144 + (aData[j+1]-128)*4096 + (aData[j+2]-128)*64 + (aData[j+3]-128);
i++;
j+=4;
}
else if(c>=248 && c<=251)
{
aValue[i]=(c-248)*16777216 + (aData[j+1]-128)*262144+ (aData[j+2]-128)*4096 + (aData[j+3]-128)*64 + (aData[j+4]-128);
i++;
j+=5;
}
else
j+=1;
}
return aValue;
}
#4
Your question doesn't say specifically which character set you want to convert to. If you only want the basic 7-bit ASCII charset, discarding every character with a higher value than 127 will work.
您的问题没有明确说明要转换为哪个字符集。如果您只需要基本的7位ASCII字符集,则丢弃值高于127的每个字符都可以。
If you want to convert to a 8-bit character set, such as latin1, you'll have to do it the hard way.
如果你想转换成8位字符集,比如latin1,你就必须这么做。
#1
You are best off reading all the other questions on SO that are tagged unicode and c++. For starters you should probably look at this one and see whether library in the accepted answer (UTF8-CPP) works for you.
你最好阅读有关标记为unicode和c ++的所有其他问题。对于初学者,你应该看看这个,看看接受的答案(UTF8-CPP)中的库是否适合你。
I would however first think about what you're trying to achieve, as there is no way you can just import UTF-8-encoded strings into "Ansi" (what ever you mean by that, maybe something like ISO8859_1 or WIN1252 encoding?).
然而,我会首先考虑你想要实现的目标,因为你无法将UTF-8编码的字符串导入“Ansi”(你的意思是什么,也许像ISO8859_1或WIN1252编码?) 。
#2
Here is a more VCL-centric approach for you:
这是一个更加以VCL为中心的方法:
UTF8String utf8 = "...";
WideString utf16;
AnsiString latin1;
int len = ::MultiByteToWideChar(CP_UTF8, 0, utf8.c_str(), utf8.Length(), NULL, 0);
utf16.SetLength(len);
::MultiByteToWideChar(CP_UTF8, 0, utf8.c_str(), utf8.Length(), utf16.c_bstr(), len);
len = ::WideCharToMultiByte(1252, 0, utf16.c_bstr(), utf16.Length(), NULL, 0, NULL, NULL);
latin1.SetLength(len);
::WideCharToMultiByte(1252, 0, utf16.c_bstr(), utf16.Length(), latin1.c_str(), len, NULL, NULL);
If you upgrade to CB2009, you can simplify it to this:
如果升级到CB2009,可以将其简化为:
UTF8String utf8 = "...";
AnsiString<1252> latin1 = utf8;
#3
As there is no-one working on weekends, I have to answer it myself :)
由于没有人在周末工作,我必须自己回答:)
String Utf8ToWinLatin1(char* aData, char* aValue)
{
int i=0;
for(int j=0;j<strlen(aData);)
{ int val=aData[j];
int c=(unsigned char)aData[j];
if(c<=127)
{ aValue[i]=c;
j+=1;
i++;
}
else if(c>=192 && c<=223)
{
aValue[i]=(c-192)*64 + (aData[j+1]-128);
i++;
j+=2;
}
else if(c>=224 && c<=239)
{
aValue[i]=( c-224)*4096 + (aData[j+1]-128)*64 + (aData[j+2]-128);
i++;
j+=3;
}
else if(c>=240 && c<=247)
{
aValue[i]=(c-240)*262144 + (aData[j+1]-128)*4096 + (aData[j+2]-128)*64 + (aData[j+3]-128);
i++;
j+=4;
}
else if(c>=248 && c<=251)
{
aValue[i]=(c-248)*16777216 + (aData[j+1]-128)*262144+ (aData[j+2]-128)*4096 + (aData[j+3]-128)*64 + (aData[j+4]-128);
i++;
j+=5;
}
else
j+=1;
}
return aValue;
}
#4
Your question doesn't say specifically which character set you want to convert to. If you only want the basic 7-bit ASCII charset, discarding every character with a higher value than 127 will work.
您的问题没有明确说明要转换为哪个字符集。如果您只需要基本的7位ASCII字符集,则丢弃值高于127的每个字符都可以。
If you want to convert to a 8-bit character set, such as latin1, you'll have to do it the hard way.
如果你想转换成8位字符集,比如latin1,你就必须这么做。