第9周任务4

时间:2022-08-05 08:03:55
#include <iostream>   
using namespace std;  
#include "p.h"

  

class Douary  
{  
public:  
    Douary(int m, int n);//构造函数:用于建立动态数组存放m行n列的二维数组(矩阵)元素,并将该数组元素初始化为   
    Douary(const Douary &d);//构造函数:用于建立动态数组存放m行n列的二维数组(矩阵)元素,并将该数组元素初始化为   
    ~Douary(); //析构函数:用于释放动态数组所占用的存储空间   
    friend istream &operator>>(istream &input, Douary &d);//重载运算符“>>”输入二维数组,其中d为Dousry类对象;   
    friend ostream &operator<<(ostream &output, Douary &d);//重载运算符“<<”以m行n列矩阵的形式输出二维数组,其中d为Douary类对象。   
    friend Douary operator+(const Douary &d1,const Douary &d2);//两个矩阵相加,规则:对应位置上的元素相加   
    friend Douary operator-(const Douary &d1,const Douary &d2);//两个矩阵相减,规则:对应位置上的元素相减   
    bool operator==(const Douary &d);//判断两个矩阵是否相等,即对应位置上的所有元素是否相等   
private:  
    int * Array;      //Array 为动态数组指针。   
    int row;          //row  为二维数组的行数。   
    int col;          //col   为二维数组的列数。   
};  
Douary::Douary(int m, int n)  
{  
    row=m;  
    col=n;  
    Array = new int[m*n]; 
    for(int i=0; i<row; i++)  
        for(int j=0; j<col; j++)  
            Array[i*col+j]=0; 
}  
  
Douary::Douary(const Douary &d)  
{  
    row=d.row;  
    col=d.col;  
    Array = new int[row*col];  
    for(int i=0; i<row; i++)  
 {

        for(int j=0; j<col; j++) 
  {

            Array[i*col+j]=d.Array[i*col+j]; 
  }
 }

}  
  
Douary::~Douary() //析构函数:用于释放动态数组所占用的存储空间   
{  
    delete [] Array;  
}  
  
istream &operator>>(istream &input, Douary &d) 
{  
    for(int i=0; i<d.row; ++i) 
 {
        for(int j=0; j<d.col; ++j)  
  {

            cin>>d.Array[i*d.col+j];  
  }
 }

    return input;  
}  
  
ostream &operator<<(ostream &output, Douary &d)  
{  
    for(int i=0; i<d.row; ++i)  
    {  
        for(int j=0; j<d.col; ++j)  
            cout<<d.Array[i*d.col+j]<<"\t"; 
        cout<<endl;  
    }  
    cout<<endl;  
    return output;  
}  
  
Douary operator+(const Douary &d1,const Douary &d2)//两个矩阵相加,规则:对应位置上的元素相加   
{  
       
    Douary d(d1.row,d1.col);  
    for(int i=0; i<d1.row; ++i)  
    {  
        for(int j=0; j<d1.col; ++j)  
            d.Array[i*d1.col+j]=d1.Array[i*d1.col+j]+d2.Array[i*d1.col+j];  
    }  
    return d;  
}  
  
Douary operator-(const Douary &d1,const Douary &d2)//两个矩阵相减,规则:对应位置上的元素相减   
{  
   
    Douary d(d1.row,d1.col);  
    for(int i=0; i<d1.row; ++i)  
    {  
        for(int j=0; j<d1.col; ++j)  
  {

            d.Array[i*d1.col+j]=d1.Array[i*d1.col+j]-d2.Array[i*d1.col+j];  
  }

    }  
    return d;  
}  
bool Douary::operator ==(const Douary &d)//判断两个矩阵是否相等,即对应位置上的所有元素是否相等   
{  
    if(row!=d.row||col!=d.col) 
  return false;  
    bool flag = true;  
    for(int i=0; i<row; ++i)  
    {  
        for(int j=0; j<col; ++j)  
  {
            if (Array[i*col+j]!=d.Array[i*col+j])   
            {  
                flag=false;  
                break;  
            }  
            //if (!flag) break;  
  }

    }  
    return flag;  
}  
  
int main()  
{  
    Douary d1(3,5),d2(3,5);  
    cout<<"输入d1(3,5):"<<endl;  
    cin>>d1;  
    cout<<"输入d2(3,5):"<<endl;  
    cin>>d2;  
    cout<<"d1="<<endl;  
    cout<<d1;  
    cout<<"d2="<<endl;  
    cout<<d2;  
    cout<<"d1+d2="<<endl;  
    Douary d3=(d1+d2);  
    cout<<d3;  
    cout<<"d1-d2="<<endl;  
    cout<<(d1-d2);  
    cout<<"d1"<<((d1==d2)?"==":"!=")<<"d2"<<endl;  
    system("pause");  
    return 0;  
}  


第9周任务4

感悟:

老师:if (!flag) break    是啥意思啊?没有它不也行吗?