用引号将数组转换为一个数组

I currently have a string, that's supposed to be an Array:

我现在有一个字符串，它应该是一个数组:

var content = "['A','B','C']"
//What I want -> var content = ['A', 'B', 'C']

I need to remove the quotation marks, so that it's just an Array, i.e. String to Array. How would one attempt that?

我需要去掉引号，这样它就是一个数组，也就是说，从字符串到数组。怎么做呢?

3 个解决方案

#1

This looks similar to JSON syntax except that the single quotes should be double quotes.

这看起来类似于JSON语法，除了单引号应该是双引号。

Well then, let's just do that:

那么，我们就这么做:

let source = "['A','B','C']"

Replace single quotes with double quotes:

用双引号替换单引号:

let content = source.stringByReplacingOccurrencesOfString("'", withString: "\"")

Then convert the String to NSData (becomes valid JSON):

然后将字符串转换为NSData(变为有效的JSON):

guard let data = content.dataUsingEncoding(NSUTF8StringEncoding) else { fatalError() }

Finally, convert the JSON data back to a Swift array of Strings:

最后，将JSON数据转换回Swift字符串数组:

guard let arrayOfStrings = try NSJSONSerialization.JSONObjectWithData(data, options: []) as? [String] else { fatalError() }

Result:

结果:

print(arrayOfStrings)

["A", "B", "C"]

(“A”、“B”、“C”)

print(arrayOfStrings[1])

"B"

“B”

#2

Here's a semi-hacky solution to your specific example.

这是对您的特定示例的一种半陈腐的解决方案。

let content = "['A','B','C']"
var characters = content.characters
characters.removeFirst(2) // Remove ['
characters.removeLast(2)  // Remove ']
let contentArray = String(characters).componentsSeparatedByString("','")
print(contentArray) // ["A", "B", "C"]

Disclaimer/Warning: This solution isn't robust as it expects your array to only contain objects wrapped in ' characters. It will however work for any length of string (e.g. replacing A with foo will work).

免责声明/警告:该解决方案并不健壮，因为它期望您的数组只包含“字符”包装的对象。但是它对任何长度的字符串都有效(例如用foo替换A就可以)。

If your actual content string is any more complex than what you have here then I would take Rob's advice and try JSON serialization (especially if this string comes from a place you don't control like the server).

如果您的实际内容字符串比这里的更复杂，那么我将采纳Rob的建议并尝试JSON序列化(特别是如果这个字符串来自一个您不喜欢服务器的地方)。

#3

You could do this one:

你可以这样做:

let arr = content.componentsSeparatedByCharactersInSet(NSCharacterSet (charactersInString: "['],")).filter({!$0.isEmpty})

Explanation:

解释:

First, we split the string into an array based upon separators like: [, ', ,, ]

首先，我们基于以下分隔符将字符串分割为数组:[，'，]
We now have an array with some empty strings, we use filter() to remove them.

我们现在有一个带一些空字符串的数组，我们使用filter()来删除它们。
And Voila !

瞧!

Warning:

警告:

like @nebs' warning, carefull with this solution. If your string is composed by more complexe strings (ex: "['Hello [buddy]', 'What's up?', 'This is a long text, or not?']"), especially string composed with the separators, you will get an array that will not match with your expected result.

就像@nebs的警告一样，小心这个解决方案。如果你的字符串是由更复杂的字符串组成的(例如:“['Hello [buddy]]'， 'What's up?，“这是一个长文本，或者不是?”)，特别是用分隔符组成的字符串，您将得到一个与预期结果不匹配的数组。

#1