如何从数组中删除一些元素？

I have the question: The program can delete clothing based on a given serial code.
I do not know how to delete some elements when it based on a given thing. On Case 3, Pls help me.

我有一个问题：该程序可以根据给定的串行代码删除服装。基于给定的东西，我不知道如何删除一些元素。在案例3中，请帮助我。

import javax.swing.*;
public class piashop
{
public static void main (String args[])
    {
      Piafashion piatest[] = new Piafashion [370];
        JOptionPane.showMessageDialog (null, "Welcome to Pia Fashion Shop");
        int no_of_clothing = 0;
        int choice = 0;
        boolean found;
        String piatargetcode, piatargetcode1;
            do
            {
                choice = Integer.parseInt(JOptionPane.showInputDialog (null, "1. Add Product  2. Report  3. Delete"));
                switch(choice)
            {
                case 1:
                    String piascode = JOptionPane.showInputDialog (null, "Enter Brand ID");
                    String piapp = JOptionPane.showInputDialog (null, "Enter Purpose");
                    String piab = JOptionPane.showInputDialog (null, "Enter Brand");
                    String piac = JOptionPane.showInputDialog (null, "Enter Colour");
                    String pias = JOptionPane.showInputDialog (null, "Enter Size");
                    double piapr = Double.parseDouble(JOptionPane.showInputDialog (null, "Enter Price"));
                    piatest [no_of_clothing] = new Piafashion (piascode, piapp, piab, piac, pias, piapr);
                        no_of_clothing++;
                        break;
                //case 1 for adding elements array into database    

                case 2:
                    String piareport ="";
                    for (int x=0; x < no_of_clothing; x++)
                    piareport = piareport + "\nBrand ID is "+piatest[x].piaserial_code + "\nPurpose is " +piatest[x].piapurpose + "\nBrand is " +piatest[x].piabrand + "\nColour is " + piatest[x].piacolour + "\nSize is " + piatest[x].piasize + "\nPrice is " + piatest[x].piaprice +"\n";

                    JOptionPane.showMessageDialog(null, piareport);

                    break;

                //case 2 for displaying the product info                                            

                case 3:
                    }
                        }while(choice!=4);
                        }
    }

1 个解决方案

#1

I would not suggest using an array - when you have the magic of collections. Deleting an element from an array requires 'reshuffling' the entire array to remove the 'gap' or writing code so that the contents of each location within the array is checked before access. Not to mention arrays are fixed size (must be extended to add more).

我不建议使用数组 - 当你拥有收藏的魔力时。从数组中删除元素需要对整个数组进行“重组”以删除“间隙”或编写代码，以便在访问之前检查数组中每个位置的内容。更不用说数组是固定大小的（必须扩展才能添加更多）。

You have the generic type ArrayList that can be used here, which supports methods like .remove(T) and .add(T).

您可以在此处使用泛型类型ArrayList，它支持.remove（T）和.add（T）等方法。

Plus this looks like a homework problem :) You probably have a textbook or classmate that can answer this in the context of your class.

另外，这看起来像是一个家庭作业问题:)你可能有一本教科书或同学可以在课堂上下文中回答这个问题。

P.S. that code is very very badly optimized - an array list would speed it up considerably (or even a HashMap)

附：该代码非常非常优化 - 数组列表会大大加快它（甚至是HashMap）

#1