如何计算一般数组中的每个唯一元素

Good day.

Code:

array(4) { 
    [0]=> array(1) { 
          [0]=> array(3) { 
               [0]=> string(11) "art_7880" [1]=> string(1) "1" [2]=> int(2950) 
          }
          [1]=> array(3) { 
               [0]=> string(8) "art_7880" [1]=> string(1) "1" [2]=> int(2955)  
          } 
          [2]=> array(3) { 
               [0]=> string(8) "art_7880" [1]=> string(1) "1" [2]=> int(1335)  
          }
          [3]=> array(3) { 
               [0]=> string(8) "art_7883" [1]=> string(1) "1" [2]=> int(4335)  
          }
}

I get array unique elements:

我得到数组独特的元素:

$arr_uniq = array();
foreach ($all_array as $keys => $elms ) {
    if(!in_array($elms[0], $arr_uniq)) {
        $arr_uniq[] = $elms[0];
    }
}

Tell me pleasse how to get a count each unique element in the general array?

告诉我如何计算一般数组中每个独特元素的数量?

result should been next:

结果应该是下一个:

art_7880 - 3

art_7880 - 3

art_7883 - 1

art_7883 - 1

2 个解决方案

#1

Assuming $all_array is subarray of your main array in your var_dump snipett, the general idea is

假设$ all_array是var_dump snipett中主数组的子数组,一般的想法是

$result = array();
foreach ($all_array as $elms)    
    $result[$elms[0]]++;

#2

array_count_values()

http://php.net/array_count_values

You should be able to easily apply this function.

您应该能够轻松应用此功能。

#1