数组到字符串转换错误的循环使用CI。

Please help, why I received Message: Array to string conversion

请帮忙，为什么我收到消息:数组到字符串转换。

Here's my code.

这是我的代码。

$remaining = 15000;
$amort = 3600;
$sales_mi = 3600;

for($remaining += $amort; $remaining > $amort; ($hi = ($remaining-=$amort) < $amort ? $remaining  : $amort) . 
    (($hi == $sales_mi) ? $data = array('amount'=>$hi)  : 'No') 
);

print_r($data);

1 个解决方案

#1

I took the liberty of rewriting your loop to make it readable:

我冒昧地重写了你的循环，让它可读:

for($remaining += $amort; $remaining > $amort; $remaining -= $amort) {
    $hi = ($remaining) < $amort ? $remaining  : $amort;
    $hi .= ($hi == $sales_mi) ? $data = array('amount'=>$hi)  : 'No';
}

Now: In the second line of the body of the loop you are returning an array if the condition $hi == $sales_mi is true. And you are attaching that array as if it were a string (using the "." operator) to the $hi variable. That's why you have that error.

现在:在循环体的第二行中，如果条件$hi == $sales_mi是正确的，则返回一个数组。然后，您将该数组附加到$hi变量中，就好像它是一个字符串(使用“.”操作符)。这就是为什么会有这个错误。