从类型'char *'分配类型'char [5]'时出现不兼容的类型

char types[5];
        switch(buffer[9]){
            case 1:
                types = "ICMP";
                break;

error:

 incompatible types when assigning to type 'char[5]' from type 'char *'

how would I fix this error?

我该如何解决这个错误?

Thanks.

1 个解决方案

#1

You can't fix it without changing its type.

如果不更改类型,则无法修复它。

Array values are not modifiable l-values. If you plan to always assign it a string literal, declare it as const char * instead of array:

数组值不是可修改的l值。如果您计划始终为其分配字符串文字,请将其声明为const char *而不是array:

const char *types;
switch(buffer[9]){
    case 1:
    types = "ICMP";
    break;

If you want to later change the contents of types, then keep it as an array and just use strcpy() or the safer variant strncpy():

如果您想稍后更改类型的内容,请将其保存为数组,并使用strcpy()或更安全的变量strncpy():

char types[5];
switch(buffer[9]){
    case 1:
    strncpy(types, "ICMP", sizeof(types));
    break;