分配到类型结构时不兼容的类型。

I'm writing a simple game and I've recently encountered problem that doesn't seem difficult to solve, however I'm out of ideas.

我正在写一个简单的游戏，最近我遇到了一个看起来并不难解决的问题，但是我没有办法。

in file blocks.c among other functions I've defined a simple function:

在文件块。在其他函数中，我定义了一个简单的函数:

field block_get_field_coordinates(int x, int y)
{
    field temp;

    temp.x = floor( x / 65 ) * 65 + 15;
    temp.y = floor( y / 65) * 65 + 15;
    return temp;
}

field is a struct declared in file grid.h

字段是在文件网格中声明的结构。

struct field
{
    int x, y;
}f;

typedef struct field field;

And in main.c when I tried the following:

并在主。当我尝试以下的方法:

f = block_get_field_coordinates(blocks[x][y].x4, blocks[x][x].y4);

Where f is 'field' I got an error:

在f 'field'我得到一个错误:

incompatible types when assigning to type 'struct field' from type 'int'

I really don't know what I've done wrong here. Other functions from blocks.c work without throwing out any errors.

我真的不知道我在这里做错了什么。其他功能块。工作时不抛出任何错误。

Interestingly, when I copied just the declaration of struct field, function block_get_field_coordinates into separate file, it worked.

有趣的是，当我仅复制struct字段的声明时，函数block_get_field_坐标转换为单独的文件，它起作用了。

1 个解决方案

#1

You need your main to see a declaration of the function.

您需要您的main来查看函数的声明。

e.g. in main

如在主

extern field block_get_field_coordinates(int x, int y);

or better yet put it in block.h as main is going to need the type as well as any functions that use the type.

或者更好的是把它放在一块。h作为main将需要类型以及任何使用类型的函数。

#1