如何根据node js中的另一个对象数组值对对象数组进行排序

How can we sort the object array based on another object array value, like we have an object array:

如何根据另一个对象数组值对对象数组进行排序，就像我们有一个对象数组:

var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}]

In this the index 1,2,3,4,5 are having the same value of the key "tEnd" i.e., 3 and 1 so I just need to sort only those index on the basis of another object array

在这里，索引1、2、3、4、5的值与key“tEnd”的值相同。3和1所以我只需要根据另一个对象数组对这些索引进行排序

var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}]

Here the userID 597,605,617,553,616 are having the score value 85,95,85,100,95

这里的userID 597,605,617,553,616的分数是85,95,85,100,95

so based on score, I want to sort my first array Output should be:

基于分数，我想排序我的第一个数组输出应该是:

[{"userID":554,"tEnd":6},{"userID":605,"tEnd":3},{"userID":597,"tEnd":3},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":617,"tEnd":1},{"userID":596,"tEnd":0}]

3 个解决方案

#1

Create an object of score by userID using Array.reduce. Sort by tEnd, and if it's equal sort by the score you get from the sortObject by the userId:

使用Array.reduce使用userID创建一个score对象。按倾向排序，如果按用户id从sortObject中得到的分数排序:

var _userEnd = [{"userID":554,"tEnd":6},{"userID":597,"tEnd":3},{"userID":605,"tEnd":3},{"userID":617,"tEnd":1},{"userID":553,"tEnd":1},{"userID":616,"tEnd":1},{"userID":596,"tEnd":0}]

var _profsort=[{"userID":596,"score":100},{"userID":616,"score":95},{"userID":553,"score":100},{"userID":617,"score":85},{"userID":605,"score":95},{"userID":597,"score":85},{"userID":554,"score":100}]

var sortObj = _profsort.reduce((r, o) => {
  r[o.userID] = o.score;

  return r;
}, Object.create(null));

_userEnd.sort((a, b) => b.tEnd - a.tEnd || sortObj[b.userID] - sortObj[a.userID]);

console.log(_userEnd);

#2

You could take the delta of tEnd and find the score and take that delta.

你可以取倾斜度的值然后取这个值。

function getScore(uID) {
    return (_profsort.find(({ userID }) => userID === uID) || { score: 0 }).score;
}

var _userEnd = [{ userID: 554, tEnd: 6 }, { userID: 597, tEnd: 3 }, { userID: 605, tEnd: 3 }, { userID: 617, tEnd: 1 }, { userID: 553, tEnd: 1 }, { userID: 616, tEnd: 1 }, { userID: 596, tEnd: 0 }],
    _profsort = [{ userID: 596, score: 100 }, { userID: 616, score: 95 }, { userID: 553, score: 100 }, { userID: 617, score: 85 }, { userID: 605, score: 95 }, { userID: 597, score: 85 }, { userID: 554, score: 100 }];
    
_userEnd.sort(function (a, b) {
    return b.tEnd - a.tEnd || getScore(b.userID) - getScore(a.userID);
});

console.log(_userEnd);

.as-console-wrapper { max-height: 100% !important; top: 0; }

#3

Use sort and find

使用排序和查找

var fnGetScore = uid => _profsort.find(s => s.userID == uid).score; //method to get the score value based on userId

var output = _userEnd.sort( (a, b) => 
        (b.tEnd - a.tEnd) || 
           fnGetScore(b.userID) - fnGetScore(b.userID)) //compare tEnd first and if they are same, compare the score value

Demo

演示

var _userEnd = [{
  "userID": 554,
  "tEnd": 6
}, {
  "userID": 597,
  "tEnd": 3
}, {
  "userID": 605,
  "tEnd": 3
}, {
  "userID": 617,
  "tEnd": 1
}, {
  "userID": 553,
  "tEnd": 1
}, {
  "userID": 616,
  "tEnd": 1
}, {
  "userID": 596,
  "tEnd": 0
}];

var _profsort = [{
  "userID": 596,
  "score": 100
}, {
  "userID": 616,
  "score": 95
}, {
  "userID": 553,
  "score": 100
}, {
  "userID": 617,
  "score": 85
}, {
  "userID": 605,
  "score": 95
}, {
  "userID": 597,
  "score": 85
}, {
  "userID": 554,
  "score": 100
}];

var fnGetScore = uid => _profsort.find(s => s.userID == uid).score;

var output = _userEnd.sort((a, b) => (b.tEnd - a.tEnd) || fnGetScore(b.userID) - fnGetScore(b.userID))

console.log(output);

#1