Java使用泛型类型创建泛型类

时间:2021-02-27 15:29:51

I'm trying to implement a generic cache class using the DualCache library. When instantiating the DualCache class one also needs to provide a serializer instance which itself is a generic class that should be of the same type as the DualCache its attached to.

我正在尝试使用DualCache库实现通用缓存类。在实例化DualCache类时,还需要提供一个序列化程序实例,该实例本身是一个通用类,应该与其附加的DualCache类型相同。

Simply put, I need to somehow pass T's class to the JSONSerializer constructor as indicated in the code, but don't know how.

简单地说,我需要以某种方式将T的类传递给JSONSerializer构造函数,如代码所示,但不知道如何。

public class Cache<T> {
    private boolean initialized = false ;
    private ArrayList<Long> cachedItemList = new ArrayList<>() ;
    private DualCache<T> dualCache ;

    public void initialize(Context context) {
        Log.e(DEBUG_TAG, "Cache/initialize") ;
        if (!initialized) {
            dualCache = new Builder<T>(ProjectInfo.cacheName, ProjectInfo.APP_VERSION)
                    .enableLog()
                    .useReferenceInRam(ProjectInfo.diskCacheSize, new SizeOf<T>() {
                        @Override
                        public int sizeOf(T object) {
                            return ProjectInfo.diskCacheSize / numCachedItems;
                        }
                    })
                    .useSerializerInDisk(ProjectInfo.diskCacheSize, true,
                            new JsonSerializer<>(T.class), context)
                    .build() ;
            getCurrentCachedItemsList(context) ;
            printCurrentItems(context) ;
            initialized = true ;
        }
    }
}

1 个解决方案

#1


2  

Assuming there is a constructor of the form JsonSerializer<T>(Class<T>), you will need to do exactly the same thing.

假设存在JsonSerializer (Class )形式的构造函数,则需要执行完全相同的操作。

private final Class<T> clazz;

public Cache(Class<T> clazz) {
    this.clazz = clazz;
}

public void initialize(Context context) {
    ...
                        new JsonSerializer<>(clazz), context)

#1


2  

Assuming there is a constructor of the form JsonSerializer<T>(Class<T>), you will need to do exactly the same thing.

假设存在JsonSerializer (Class )形式的构造函数,则需要执行完全相同的操作。

private final Class<T> clazz;

public Cache(Class<T> clazz) {
    this.clazz = clazz;
}

public void initialize(Context context) {
    ...
                        new JsonSerializer<>(clazz), context)