如何在php数组及其索引中获取前3个值

I want to get the highest value, the second highest value and the third highest value

我想要得到最高的值，第二高的值和第三高的值

For example, I have an array like:

例如，我有一个数组，比如:

$n = array(100,90,150,200,199,155,15,186);

$ n =数组(100、90150200199155、15186);

I know the method to get the max value and its index:

我知道求最大值的方法及其指标:

echo max($n); //200 $maxs = array_keys($n, max($n)); echo $maxs[0]; //3

回声马克斯($ n);//200 $maxs = array_keys($n, max($n));echo $马克斯[0];/ / 3

I want to get the top 3 values and their index like : value: 200, 199, 186 index:3,4,7

我想要得到前3个值以及它们的索引:value: 200,199,186 index:3,4,7

How can i get them?

我怎样才能得到它们?

5 个解决方案

#1

Try this:

试试这个:

$n = array(100,90,150,200,199,155,15,186);
rsort($n);
$top3 = array_slice($n, 0, 3);
echo 'Values: ';
foreach ($top3 as $key => $val) {
 echo "$val\n";
}
echo '<br>';
echo 'Keys: ';
foreach ($top3 as $key => $val) {
echo "$key\n";
}

Output:

输出:

Values: 200 199 186 
Keys: 0 1 2

#2

This should do the trick:

这应该能达到目的:

function maxNitems($array, $n = 3){
    asort($array);
    return array_slice(array_reverse($array, true),0,$n, true);
}

Use like:

使用:

maxNitems(array(100,90,150,200,199,155,15,186));

#3

You can achieve it by using arsort() and array_keys() functions:

可以通过使用arsort()和array_keys()函数实现:

arsort() sorts an array in reverse order and maintains index association
arsort()对数组进行反向排序并保持索引关联
array_keys() returns all the keys or a subset of the keys of an array
array_keys()返回数组的所有键或键的子集

Process array:

过程数组:

$n = array(100,90,150,200,199,155,15,186);
arsort($n);
$keys = array_keys($n);

Get top 3 values:

获得前三值:

echo $n[$keys[0]];
echo $n[$keys[1]];
echo $n[$keys[2]];

#4

$n = array(100,90,150,200,199,155,15,186);
arsort($n);

$x = 0;
while (++$x <= 3)
{
    $key = key($n);
    $value = current($n);
    next($n);
    echo "Key : " . $key . " Value  : " . $value . '<br>' ;
}

#5

Easier I would think:

简单的我认为:

arsort($n);
$three = array_chunk($n, 3, true)[0];
//or
$three = array_slice($n, 0, 3, true);

#1