I have two arrays which product IDs storing as keys.
我有两个数组,产品ID存储为键。
First array goes like :
第一个数组如下:
Array
(
[1] => Array
(
[_sku] =>
[_qty] => 1
)
[34] => Array
(
[_sku] =>
[_qty] => 3
)
[23] => Array
(
[_sku] =>
[_qty] => 1
)
)
Second array goes like :
第二个数组如下:
Array
(
[1] => Array
(
[_sku] =>
[_qty] => 1
)
[54] => Array
(
[_sku] =>
[_qty] => 1
)
)
My first array is the logged in user's basket. Second is the same user's not logged in basket. When user logged in I have to compere these 2 arrays and add the missing keys to first array but if the same keys exists in two arrays I have to roundup the first array's _qty with second's _qty (like : [1] => _qty is 1 and second array has also 1 qty so make firsts qty = 2 ). or process what I want and create a third array also possible I guess.
我的第一个数组是登录用户的篮子。第二个是同一个用户没有登录篮子。当用户登录时,我必须主持这两个数组,并将缺少的键添加到第一个数组,但如果两个数组中存在相同的键,我必须用第二个_qty对第一个数组的_qty进行四舍五入(如:[1] => _qty为1第二个数组也有1个数量,所以第一个数字= 2)。或者我可以处理我想要的并创建第三个数组。
How to achive this?
如何实现这一目标?
1 个解决方案
#1
1
A simple foreach
should do the trick:
一个简单的foreach应该做的伎俩:
foreach ($second as $key => $value) {
if (isset($first[$key])) {
$first[$key]['_qty'] += $value['_qty'];
} else {
$first[$key] = $value;
}
}
#1
1
A simple foreach
should do the trick:
一个简单的foreach应该做的伎俩:
foreach ($second as $key => $value) {
if (isset($first[$key])) {
$first[$key]['_qty'] += $value['_qty'];
} else {
$first[$key] = $value;
}
}