PHP和2多维数组基于两个键值进行比较

I have two multidimensional arrays like this:

我有两个这样的多维数组:

$original = Array (
[0] => Array
    (
        [time] => 1364690340
        [memberid] => 90
        [type] => single
    )

[1] => Array
    (
        [time] => 1364690341
        [memberid] => 92
        [type] => fixed
    )

[2] => Array
    (
        [time] => 1364690342
        [memberid] => 96
        [type] => single
    )
)

and second one like this

第二个是这样的

$new = Array (
[0] => Array
    (
        [time] => 1364825750
        [memberid] => 90
        [type] => single
    )

[1] => Array
    (
        [time] => 1364825751
        [memberid] => 92
        [type] => single
    )

[2] => Array
    (
        [time] => 1364825752
        [memberid] => 96
        [type] => single
    )

[3] => Array
    (
        [time] => 1364825753
        [memberid] => 111
        [type] => single
    )
)

My problem is: I want to search $original array for matches based on memberid and type keys and if memberid and type ARE NOT the same -> I want to remove that array from $original array. So in this case I want to keep [0] Array and [2] Array as in $new array I have same memberid and same type as in original, but I would want to remove [1] Array as memberid is the same, but type is different. So my final $original array will look like this:

我的问题是:我想基于memberid和类型键搜索$ original数组的匹配,如果memberid和type不相同 - >我想从$ original数组中删除该数组。所以在这种情况下我想保持[0]数组和[2]数组,因为在$ new数组中我有相同的memberid和相同的类型,但是我想删除[1]数组,因为memberid是相同的,但是类型不同。所以我的最终$ original数组将如下所示:

$original = Array (
[0] => Array
    (
        [time] => 1364690340
        [memberid] => 90
        [type] => single
    )

[1] => Array
    (
        [time] => 1364690342
        [memberid] => 96
        [type] => single
    )
)

2 个解决方案

#1

Here you go, just tested it and it works as expected.

在这里,你去测试它,它按预期工作。

// Presuming your two arrays are still called $new & $original
$original = array(); // your data
$new = array(); // your data

$newArray = array();
foreach($original AS $key => $val){
    $newArray[$val['memberid'] . '-' . $val['type']] = $val;
}

$original = array();
foreach($new AS $key => $val){
    if(isset($newArray[$val['memberid'] . '-' . $val['type']])){
        $original[] = $newArray[$val['memberid'] . '-' . $val['type']];
    }
}

print_r($original);

#2

-1

Without making any assumptions about your data, here's an inefficient solution, O(m * n) if m and n are the lengths of your arrays:

在不对数据做任何假设的情况下,这是一个效率低下的解决方案,如果m和n是数组的长度,则为O(m * n):

$new_original = array();
foreach ($original as $elem) {
  // let's see if $new has something with the same type and memberid
  foreach ($new as $candidate) {
    if ($candidate['type'] == $elem['type'] &&
        $candidate['memberid'] == $elem['memberid']) {
      // it does! let's keep $elem
      $new_original[] = $elem;
    }
  }
}

// reassign it to $original if desired
$original = $new_original;

However, it would be much cooler to do more efficient lookups. For example, if we can assume there is at most one element with a given memberid in $new:

但是,进行更有效的查找会更酷。例如,如果我们可以假设在$ new中最多只有一个元素具有给定的memberid:

// turn $new into a map
$new_as_map = array();
foreach ($new as $candidate) {
  $new_as_map[$candidate['memberid']] = $candidate;
}

$new_original = array();
foreach ($original as $elem) {
  if (isset($new_as_map[$elem['memberid']])) {
    $candidate = $new_as_map[$elem['memberid']];
    if ($candidate['type'] == $elem['type']) {
      $new_original[] = $elem;
    }
  }
}

// reassign it to $original if desired
$original = $new_original;

#1