将数组拆分为一些子数组[重复]

时间:2022-02-27 12:17:44

Possible Duplicate:
How to split (chunk) a Ruby array into parts of X elements?

可能重复:如何将Ruby数组拆分(块)成X个元素的部分?

I would like to split an array into an array of sub-arrays.

我想将一个数组拆分成一个子数组。

For example,

例如,

big_array = (0...6).to_a

How can we cut this big array into an array of arrays (of a max length of 2 items) such as:

我们如何将这个大数组切割成一个数组(最大长度为2项),例如:

arrays = big_array.split_please(2)

Where...

哪里...

arrays # => [ [0, 1],
              [2, 3],
              [4, 5] ]

Note: I ask this question, 'cause in order to do it, I'm currently coding like this:

注意:我问这个问题,'因为为了做到这一点,我目前编码如下:

arrays = [
           big_array[0..1],
           big_array[2..3],
           big_array[4..5]
         ]

...which is so ugly. And very unmaintainable code, when big_array.length > 100.

......这太丑了。当big_array.length> 100时,代码非常难以维护。

2 个解决方案

#1


14  

You can use the #each_slice method on the array

您可以在阵列上使用#each_slice方法

big_array = (0..20).to_a
array = big_array.each_slice(2).to_a
puts array # [[0, 1], [2, 3], [4, 5], [6, 7], [8, 9], [10, 11], [12, 13], [14, 15], [16, 17], [18, 19], [20]]

#2


6  

check out the slice:

看看切片:

big_array.each_slice( 2 ).to_a

#1


14  

You can use the #each_slice method on the array

您可以在阵列上使用#each_slice方法

big_array = (0..20).to_a
array = big_array.each_slice(2).to_a
puts array # [[0, 1], [2, 3], [4, 5], [6, 7], [8, 9], [10, 11], [12, 13], [14, 15], [16, 17], [18, 19], [20]]

#2


6  

check out the slice:

看看切片:

big_array.each_slice( 2 ).to_a