I have a problem. I'm coding up a plug in for Google Sketchup and I'm trying to filter out array value and place the filtered values into another array. This is done like this:
我有个问题。我正在为Google Sketchup编写一个插件,我正在尝试过滤掉数组值并将过滤后的值放入另一个数组中。这样做是这样的:
for z in 0..points.length
points2[z]=points[z][1]
end
Where "points" is a double array. Can someone please tell me what I'm doing wrong?
其中“点”是双数组。有人可以告诉我我做错了什么吗?
3 个解决方案
#1
4
This should be better:
这应该更好:
points2 = points.map {|p| p[1]}
#2
2
What you are doing wrong is looping once to much. Using fake data:
你做错了什么就是循环一次。使用假数据:
ar = [1,2,3]
ar2 = []
for z in 0..ar.length
#off by one! Should be one less. But then you should test for empty arrays...
ar2[z] = ar[z]
end
p ar2 #[1, 2, 3, nil]
The other answers advocate map
and they are right, but you could transform the for-loop into a less error-prone one like this:
其他答案提倡地图,他们是正确的,但你可以将for-loop转换为一个不那么容易出错的地图,如下所示:
for z in ar
ar2 << z
end
#3
1
What you are doing wrong? Fan of for
loop that I am, you should use functional style, aka. Ruby way:
你做错了什么?我是for循环的粉丝,你应该使用功能风格,又名。 Ruby方式:
points2 = points.map { |element| element[1] }
Otherwise, you would have to post better example if you want people to diagnose your for loop.
否则,如果您希望人们诊断您的for循环,则必须发布更好的示例。
#1
4
This should be better:
这应该更好:
points2 = points.map {|p| p[1]}
#2
2
What you are doing wrong is looping once to much. Using fake data:
你做错了什么就是循环一次。使用假数据:
ar = [1,2,3]
ar2 = []
for z in 0..ar.length
#off by one! Should be one less. But then you should test for empty arrays...
ar2[z] = ar[z]
end
p ar2 #[1, 2, 3, nil]
The other answers advocate map
and they are right, but you could transform the for-loop into a less error-prone one like this:
其他答案提倡地图,他们是正确的,但你可以将for-loop转换为一个不那么容易出错的地图,如下所示:
for z in ar
ar2 << z
end
#3
1
What you are doing wrong? Fan of for
loop that I am, you should use functional style, aka. Ruby way:
你做错了什么?我是for循环的粉丝,你应该使用功能风格,又名。 Ruby方式:
points2 = points.map { |element| element[1] }
Otherwise, you would have to post better example if you want people to diagnose your for loop.
否则,如果您希望人们诊断您的for循环,则必须发布更好的示例。