hey i have a jquery function that is triggered on an anchor's onclick event the function is as follows:
嘿,我有一个jquery函数在锚点onclick事件上被触发函数如下:
function dropDown(subid, e) {
e.preventDefault();
var sub = '#' + subid;
// hide all submenus first
$('.subnav').css({'display' : 'none'});
//Show the Current Subnav
$(sub).css({'display' : 'block'});
}
this is how i am tring to trigger it :
这就是我如何触发它的方法:
<a href="#!" onclick="dropDown('sn_cities')" >Cities</a>
However i am getting this error: e is undefined
但是我得到这个错误:e没有定义。
i want to cancel the default onclick event of the anchor link, any help would be appreciated.
我想取消锚点链接的默认onclick事件,如有任何帮助将不胜感激。
2 个解决方案
#1
15
You're not passing the event object (or anything at all) to the e
parameter of the function. Try this:
您没有将事件对象(或任何东西)传递给函数的e参数。试试这个:
onclick="dropDown('sn_cities',event);"
I'd be inclined to lose the inline JS altogether though:
我可能会完全失去内联JS:
<a href="#!" data-dropDown="sn_cities">Cities</a>
$(document).ready(function() {
$("a[data-dropDown]").click(function(e) {
e.preventDefault();
// hide all submenus first
$('.subnav').hide();
//Show the Current Subnav
$('#' + $(this).attr("data-dropDown")).show();
});
});
#2
0
function dropDown(subid) {
var sub = '#' + subid;
// hide all submenus first
$('.subnav').css({'display' : 'none'});
//Show the Current Subnav
$(sub).css({'display' : 'block'});
}
<a href="#!" onclick="dropDown('sn_cities'); return false;" >Cities</a>
As a side note. Inline-javascript is not recommended. Keep your scripts in an external file for clarity.
作为边注。不推荐内联javascript。将您的脚本保存在外部文件中以保持清晰。
#1
15
You're not passing the event object (or anything at all) to the e
parameter of the function. Try this:
您没有将事件对象(或任何东西)传递给函数的e参数。试试这个:
onclick="dropDown('sn_cities',event);"
I'd be inclined to lose the inline JS altogether though:
我可能会完全失去内联JS:
<a href="#!" data-dropDown="sn_cities">Cities</a>
$(document).ready(function() {
$("a[data-dropDown]").click(function(e) {
e.preventDefault();
// hide all submenus first
$('.subnav').hide();
//Show the Current Subnav
$('#' + $(this).attr("data-dropDown")).show();
});
});
#2
0
function dropDown(subid) {
var sub = '#' + subid;
// hide all submenus first
$('.subnav').css({'display' : 'none'});
//Show the Current Subnav
$(sub).css({'display' : 'block'});
}
<a href="#!" onclick="dropDown('sn_cities'); return false;" >Cities</a>
As a side note. Inline-javascript is not recommended. Keep your scripts in an external file for clarity.
作为边注。不推荐内联javascript。将您的脚本保存在外部文件中以保持清晰。