Possible Duplicate:
What is the * operator doing to this string in Ruby可能重复：*运算符在Ruby中对此字符串执行的操作是什么
Probably there is answer for that elsewhere, but I just don't know how to find it...
可能在其他地方有答案，但我只是不知道如何找到它...
If I am right, the * means multiple parameters if used in function definition:
如果我是对的，*表示在函数定义中使用的多个参数：
def hero(name, *super_powers)
But what does * do in the code like this:
但是*在代码中做了什么：
Hash[*[[:first_name, 'Shane'], [:last_name, 'Harvie']].flatten] # => {:first_name=>"Shane", :last_name=>"Harvie"}
1 个解决方案
#1
39
Variable Length Argument List, Asterisk Operator
可变长度参数列表，星号运算符
The last parameter of a method may be preceded by an asterisk(*), which is sometimes called the 'splat' operator. This indicates that more parameters may be passed to the function. Those parameters are collected up and an array is created.
方法的最后一个参数可以在前面加上星号（*），有时也称为“splat”运算符。这表示可以将更多参数传递给函数。收集这些参数并创建一个数组。
The asterisk operator may also precede an Array argument in a method call. In this case the Array will be expanded and the values passed in as if they were separated by commas.
星号运算符也可以在方法调用中的Array参数之前。在这种情况下，将展开数组并传入值，就好像它们用逗号分隔一样。
#1
39
Variable Length Argument List, Asterisk Operator
可变长度参数列表，星号运算符
The last parameter of a method may be preceded by an asterisk(*), which is sometimes called the 'splat' operator. This indicates that more parameters may be passed to the function. Those parameters are collected up and an array is created.
方法的最后一个参数可以在前面加上星号（*），有时也称为“splat”运算符。这表示可以将更多参数传递给函数。收集这些参数并创建一个数组。
The asterisk operator may also precede an Array argument in a method call. In this case the Array will be expanded and the values passed in as if they were separated by commas.
星号运算符也可以在方法调用中的Array参数之前。在这种情况下，将展开数组并传入值，就好像它们用逗号分隔一样。