我如何计算两个日期之间的差异?

How can I calculate the days between 1 Jan 2010 and (for example) 3 Feb 2010?

如何计算2010年1月1日至(例如)2010年2月3日之间的天数?

6 个解决方案

#1

NSDate *date1 = [NSDate dateWithString:@"2010-01-01 00:00:00 +0000"];
NSDate *date2 = [NSDate dateWithString:@"2010-02-03 00:00:00 +0000"];

NSTimeInterval secondsBetween = [date2 timeIntervalSinceDate:date1];

int numberOfDays = secondsBetween / 86400;

NSLog(@"There are %d days in between the two dates.", numberOfDays);

EDIT:

Remember, NSDate objects represent exact moments of time, they do not have any associated time-zone information. When you convert a string to a date using e.g. an NSDateFormatter, the NSDateFormatter converts the time from the configured timezone. Therefore, the number of seconds between two NSDate objects will always be time-zone-agnostic.

记住，NSDate对象表示精确的时间时刻，它们没有任何相关的时区信息。当您使用例如NSDateFormatter将字符串转换为日期时，NSDateFormatter将从配置的时区转换时间。因此，两个NSDate对象之间的秒数总是与时间无关的。

Furthermore, this documentation specifies that Cocoa's implementation of time does not account for leap seconds, so if you require such accuracy, you will need to roll your own implementation.

此外，该文档指定Cocoa的时间实现不考虑闰秒，因此如果您需要这样的精度，您将需要滚动自己的实现。

#2

You may want to use something like this:

你可能想用这样的东西:

NSDateComponents *components;
NSInteger days;

components = [[NSCalendar currentCalendar] components: NSDayCalendarUnit 
        fromDate: startDate toDate: endDate options: 0];
days = [components day];

I believe this method accounts for situations such as dates that span a change in daylight savings.

我相信这种方法可以解释一些情况，比如在夏令时发生变化的日期。

#3

NSTimeInterval diff = [date2 timeIntervalSinceDate:date1]; // in seconds

where date1 and date2 are NSDate's.

其中date1和date2是NSDate的。

Also, note the definition of NSTimeInterval:

还要注意NSTimeInterval的定义:

typedef double NSTimeInterval;

#4

Checkout this out. It takes care of daylight saving , leap year as it used iOS calendar to calculate.You can change the string and conditions to includes minutes with hours and days.

检测出来。它使用iOS日历计算夏令时，闰年。您可以更改字符串和条件，以包括分钟和天数。

+(NSString*)remaningTime:(NSDate*)startDate endDate:(NSDate*)endDate
{
    NSDateComponents *components;
    NSInteger days;
    NSInteger hour;
    NSInteger minutes;
    NSString *durationString;

    components = [[NSCalendar currentCalendar] components: NSCalendarUnitDay|NSCalendarUnitHour|NSCalendarUnitMinute fromDate: startDate toDate: endDate options: 0];

    days = [components day];
    hour = [components hour];
    minutes = [components minute];

    if(days>0)
    {
        if(days>1)
            durationString=[NSString stringWithFormat:@"%d days",days];
        else
            durationString=[NSString stringWithFormat:@"%d day",days];
        return durationString;
    }
    if(hour>0)
    {        
        if(hour>1)
            durationString=[NSString stringWithFormat:@"%d hours",hour];
        else
            durationString=[NSString stringWithFormat:@"%d hour",hour];
        return durationString;
    }
    if(minutes>0)
    {
        if(minutes>1)
            durationString = [NSString stringWithFormat:@"%d minutes",minutes];
        else
            durationString = [NSString stringWithFormat:@"%d minute",minutes];

        return durationString;
    }
    return @""; 
}

#5

Swift 4
Try this and see (date range with String):

Swift 4试试这个，看看(带字符串的日期范围):

// Start & End date string
let startingAt = "01/01/2018"
let endingAt = "08/03/2018"

// Sample date formatter
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "dd/MM/yyyy"

// start and end date object from string dates
var startDate = dateFormatter.date(from: startingAt) ?? Date()
let endDate = dateFormatter.date(from: endingAt) ?? Date()


// Actual operational logic
var dateRange: [String] = []
while startDate <= endDate {
    let stringDate = dateFormatter.string(from: startDate)
    startDate = Calendar.current.date(byAdding: .day, value: 1, to: startDate) ?? Date()
    dateRange.append(stringDate)
}

print("Resulting Array - \(dateRange)")

Swift 3

斯威夫特3

var date1 = Date(string: "2010-01-01 00:00:00 +0000")
var date2 = Date(string: "2010-02-03 00:00:00 +0000")
var secondsBetween: TimeInterval = date2.timeIntervalSince(date1)
var numberOfDays: Int = secondsBetween / 86400
print(numberOfDays)

#6

You can find the difference by converting the date in seconds and take time interval since 1970 for this and then you can find the difference between two dates.

您可以通过将日期转换为秒，并从1970年开始计时，然后您可以发现两个日期之间的差异。