请高手帮个忙

请问下我在jsp页面写了一个<script>

<body部分><div>  <div> <input type="button" value="添加" onclick="add()"/></div></div>

<script>

<head部分是><script type="text/javascript">
  function add(){

location.href="user!add.action";
  }

  </script> 但是我运行出来个空值提示是java.lang.IllegalArgumentException: [Assertion failed] - this argument is required; it must not be null
  请问这是什么原因啊

10 个解决方案

#1

location.href="user!add.action";
改为“window.location.href="user!add.action";

#2

我改了可是还是出那个错误到底是什么原因呢帮帮忙歇息诶了

#3

user!add.action 这里写的对吗！能让我看一下！你后台java 代码吗？

#4

该回复于2012-02-21 09:11:23被版主删除

#5

package com.secneo.action;

import java.util.List;

import org.springframework.beans.BeanUtils;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.beans.factory.annotation.Qualifier;
import org.springframework.context.annotation.Scope;
import org.springframework.stereotype.Controller;

import com.secneo.pojo.User;
import com.secneo.service.IUserService;
@Controller("userAction")
@Scope("request")
public class UserAction {
private User user;
private List<User> users;
private IUserService userService;
public List<User> getUsers() {
return users;
}
public void setUsers(List<User> users) {
this.users = users;
}

public User getUser() {
return user;
}
public void setUser(User user) {
this.user = user;
}
public IUserService getUserService() {
return userService;
}
@Autowired
public void setUserService(@Qualifier("userService") IUserService userService) {
this.userService = userService;
}

public String add(){

userService.save(user);
return "add";

}

public String list() {
users =userService.findAll();
return "list";
}

public String edit() {
user= userService.findById(user.getId());
return "edit";
}
public String save(){

return list();

}

public String update() {

User u=userService.findById(user.getId());
BeanUtils.copyProperties(user, u);
try {
userService.update(u);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return list();

}

public String view(){
user=userService.findById(user.getId());
return "view";

}

public String remove(){

userService.remove(user.getId());
return list();
}

}

#6

是不是这个页面的？

#7

java.lang.IllegalArgumentException: [Assertion failed] - this argument is required; it must not be null

方法参数错误断言失败这个论点是被需要的它不能被赋予null

首先测试程序进入你的action里面没 save 里的 user 根本就是空的你也不可能 save东西进去吧，，还有return “add” 要对应你的xml文件

#8

都new 出来看下先，是不是没有查出数据

#9

学学高手闷得解答

#10

谢谢高手们的解答

#1