I've written a number of classes using JAXB for serialization and I was wondering if there was a way to generate a XSD file for each of these objects based on the annotations. Is there a tool for this?
我已经编写了许多使用JAXB进行序列化的类，我想知道是否有一种方法可以根据注释为每个对象生成一个XSD文件。有这个工具吗？
Something like generate-xsd com/my/package/model/Unit.java would be awesome. Does anything exist to do this?
像generate-xsd com / my / package / model / Unit.java这样的东西真棒。有什么事可做吗？
1 个解决方案
#1
67
Yes, you can use the generateSchema method on JAXBContext:
是的，您可以在JAXBContext上使用generateSchema方法：
JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
SchemaOutputResolver sor = new MySchemaOutputResolver();
jaxbContext.generateSchema(sor);
You leverage an implementation of SchemaOutputResolver to control where the output goes:
您利用SchemaOutputResolver的实现来控制输出的位置：
public class MySchemaOutputResolver extends SchemaOutputResolver {
public Result createOutput(String namespaceURI, String suggestedFileName) throws IOException {
File file = new File(suggestedFileName);
StreamResult result = new StreamResult(file);
result.setSystemId(file.toURI().toURL().toString());
return result;
}
}
#1
67
Yes, you can use the generateSchema method on JAXBContext:
是的，您可以在JAXBContext上使用generateSchema方法：
JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);
SchemaOutputResolver sor = new MySchemaOutputResolver();
jaxbContext.generateSchema(sor);
You leverage an implementation of SchemaOutputResolver to control where the output goes:
您利用SchemaOutputResolver的实现来控制输出的位置：
public class MySchemaOutputResolver extends SchemaOutputResolver {
public Result createOutput(String namespaceURI, String suggestedFileName) throws IOException {
File file = new File(suggestedFileName);
StreamResult result = new StreamResult(file);
result.setSystemId(file.toURI().toURL().toString());
return result;
}
}