[算法]Python判断一个点是否在多边形内部

时间:2024-07-14 17:35:02

题目:

[算法]Python判断一个点是否在多边形内部

代码:

# -*- coding:utf-8 -*-

def rayCasting(p, poly):
px = p['x']
py = p['y']
flag = False i = 0
l = len(poly)
j = l - 1
#for(i = 0, l = poly.length, j = l - 1; i < l; j = i, i++):
while i < l:
sx = poly[i]['x']
sy = poly[i]['y']
tx = poly[j]['x']
ty = poly[j]['y'] #点与多边形顶点重合
if (sx == px and sy == py) or (tx == px and ty == py):
return (px, py) #判断线段两端点是否在射线两侧
if (sy < py and ty >= py) or (sy >= py and ty < py):
#线段上与射线 Y 坐标相同的点的 X 坐标
x = sx + (py - sy) * (tx - sx) / (ty - sy)
#点在多边形的边上
if x == px:
return (px,py)
#射线穿过多边形的边界
if x > px:
flag = not flag
j = i
i += 1 #射线穿过多边形边界的次数为奇数时点在多边形内
return (px,py) if flag else 'out' #根据数组下标奇偶数得到点的坐标
def getpoint(a):
i = 0
zhima = []
while i < len(a.split(',')[1::2]):
zhima.append({'x': float(a.split(',')[::2][i]),'y': float(a.split(',')[1::2][i])})
i += 1
return zhima #根据输入的点循环判断芝麻是否在多边形里面,如果全部在外面则输出no,否则输出芝麻的坐标
def rs(zhima, duobianxing):
zm = getpoint(zhima)
dbx = getpoint(duobianxing)
count = 0
for point in zm:
rs = rayCasting(point, dbx)
if rs == 'out':
count += 1
else:
print rs
if count == len(zm):
print "no" zhima = "6,4,8,8,9,9"
duobianxing = "1,1,7,3,5,7"
rs(zhima,duobianxing)

  

结果:

[算法]Python判断一个点是否在多边形内部