题目描述
【Speech Module】：输入一个数字，将其转换成英文表达形式，字符串中的所有单词必须以一个空格字符分隔。
【输入】：一个数字（int）
【输出】：代表数字的英文字符串（str）
【前提】：0 < number < 1000
【范例】：
checkio(4)=='four'
checkio(143)=='one hundred forty three'
checkio(12)=='twelve'
checkio(101)=='one hundred one'
checkio(212)=='two hundred twelve'
checkio(40)=='forty'
解题思路
将输入的数字分为四种情况：
0 ≤ 数字 < 10：直接返回 FIRST_TEN[number - 1] 即可；
10 ≤ 数字 < 20：直接返回 SECOND_TEN[number - 10] 即可；
20 ≤ 数字 < 100：如果是 10 的倍数（number % 10 == 0），直接返回 OTHER_TENS[number // 10 - 2] 即可，如果不是 10 的倍数（number % 10 != 0），那么就要将其十位和个位连起来，即：OTHER_TENS[number // 10 - 2] + ' ' + FIRST_TEN[number % 10 - 1]；
100 ≤ 数字 < 999：与第三种情况类似，实现判断是不是 100 的倍数，如果是则直接返回 FIRST_TEN[number // 100 - 1] + ' ' + HUNDRED，如果不是，则判断其除以 100 的余数是不是 10 的倍数，也就是后两位是不是 10 的倍数，即重复第三步即可。
代码实现
FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
HUNDRED = "hundred"
def checkio(number):
if number >= 0 and number < 10:
english = FIRST_TEN[number - 1]
return english
elif number >= 10 and number < 20:
english = SECOND_TEN[number - 10]
return english
elif number >= 20 and number < 100:
if number % 10 == 0:
english = OTHER_TENS[number // 10 - 2]
return english
else:
english = OTHER_TENS[number // 10 - 2] + ' ' + FIRST_TEN[number % 10 - 1]
return english
else:
if number % 100 == 0:
english = FIRST_TEN[number // 100 - 1] + ' ' + HUNDRED
return english
else:
english = FIRST_TEN[number // 100 - 1] + ' ' + HUNDRED + ' ' + checkio(number % 100)
return english
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(4) == 'four', "1st example"
assert checkio(133) == 'one hundred thirty three', "2nd example"
assert checkio(12) == 'twelve', "3rd example"
assert checkio(101) == 'one hundred one', "4th example"
assert checkio(212) == 'two hundred twelve', "5th example"
assert checkio(40) == 'forty', "6th example"
assert not checkio(212).endswith(' '), "Don't forget strip whitespaces at the end of string"
print('Done! Go and Check it!')
大神解答
大神解答 NO.1
def checkio(number):
"""Convert Arabic numerals to English
"""
num1 = ["", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
num11 = [
"ten",
"eleven ",
"twelve",
"thirteen",
"fourteen",
"fifteen",
"sixteen",
"seventeen",
"eighteen",
"nineteen",
]
num2 = [
"",
"",
"twenty ",
"thirty ",
"forty ",
"fifty ",
"sixty ",
"seventy ",
"eighty ",
"ninety ",
]
num3 = [
"",
"one hundred ",
"two hundred ",
"three hundred ",
"four hundred ",
"five hundred ",
"six hundred ",
"seven hundred ",
"eight hundred ",
"nine hundred ",
]
num4 = ["", "one thousand"]
if number < 10 or number > 19:
a = str(number)
if number < 10:
a = "000" + a
elif number < 100:
a = "00" + a
elif number < 1000:
a = "0" + a
if a[2] == "1":
spel = num4[int(a[0])] + num3[int(a[1])] + num11[int(a[3])]
else:
spel = num4[int(a[0])] + num3[int(a[1])] + num2[int(a[2])] + num1[int(a[3])]
else:
spel = num11[(number - 10)]
if spel[-1] == " ":
spel = spel[0:-1]
return spel
大神解答 NO.2
FIRST_TEN = ["", "one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
def checkio(number):
result = ''
if number >= 100:
result += f'{FIRST_TEN[int(number/100)]} hundred '
number %= 100
if number >= 20:
result += f'{OTHER_TENS[int(number/10)-2]} {FIRST_TEN[number % 10]}'
elif number >= 10:
result += SECOND_TEN[number % 10]
else:
result += FIRST_TEN[number]
return result.rstrip()
外汇返佣 NO.3
FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
HUNDRED = "hundred"
def checkio(number):
d = {f'x{i}': number%10**i//10**(i-1) for i in range(1, 4)}
res = ''
if d['x3']:
res += ' {} {}'.format(FIRST_TEN[d['x3'] - 1], HUNDRED)
if d['x2'] == 1:
res += ' {}'.format(SECOND_TEN[d['x1']])
elif d['x2']:
res += ' {}'.format(OTHER_TENS[d['x2'] - 2])
if d['x1'] and not (d['x2'] == 1):
res += ' {}'.format(FIRST_TEN[d['x1'] - 1])
return res.strip()
大神解答 NO.4
FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
HUNDRED = "hundred"
def checkio(number):
ret =''
h = number//100
t = (number - h*100)//10
f = number - h*100 - t*10
if h > 0:
ret += FIRST_TEN[h-1] + ' ' + HUNDRED + ' '
if t == 0 and f > 0:
ret += FIRST_TEN[f-1] + ' '
elif t == 1:
ret += SECOND_TEN[f] + ' '
elif t>1:
ret += OTHER_TENS[t-2] + ' '
if f>0:
ret += FIRST_TEN[f-1] + ' '
return ret[:-1]