PHP：如何更改SQL中的验证值？

I have this code

我有这个代码

<form action="" method="POST">
PIN: 
<input type="text" name="pin"><br />
E-Mail: 
<input type="text" name="email"><br />  
<input type="submit" value="Claim" name="submit" />
</form>


<?php
if(isset($_POST["submit"])){

if(!empty($_POST['pin']) && !empty($_POST['email'])) {
$pin=$_POST['pin'];
$email=$_POST['email'];


$con=mysql_connect('localhost','root','admin') or die(mysql_error());
mysql_select_db('user_codevalidation') or die("cannot select DB");

$sql="INSERT INTO codes(email) VALUES('$email') WHERE pin='".$dbpin."'";
mysql_query($sql);
echo "Successfully claimed!";
{
while($row=mysql_fetch_assoc($query))
{
$dbpin=$row['pin'];
}

if($pin == $dbpin)
{
$sql="INSERT INTO codes(email,claimed) VALUES('$email','1') WHERE pin = $dbpin";
echo "Successfully claimed!";
}
} else {
echo "Invalid pin or it has already been claimed once!";
}

} else {
echo "All fields are required!";
}
}
?>

I want to be able to validate pin AND if claimed = 0 in the database in the row $pin where pin is equal to the value in pin textbox $pin, if it is equal, then execute $sql which is to insert the value in email into the sql $email which is the email textbox, and then change the claimed value to '1' which is by default 0 in the database.

我希望能够验证引脚AND如果在$ pin行的数据库中声明= 0,其中pin等于pin textbox $ pin中的值,如果它相等,则执行$ sql,即插入值通过电子邮件发送到sql $ email这是电子邮件文本框,然后将声明的值更改为“1”,默认情况下为0。

I got everything working and it says 'Successfully claimed!' but it does not change my values in the database. Please help!

我把一切都搞定了,并说“成功声称!”但它不会改变我在数据库中的值。请帮忙!

Edit: I have added the execute MySQL query and it still gives me the same result!

编辑:我添加了执行MySQL查询,它仍然给我相同的结果!

3 个解决方案

#1

There is no query execution command mysql_query() Add this line after the query

没有查询执行命令mysql_query()在查询后添加此行

mysql_query($sql);

#2

You need to make sure you execute the query:

您需要确保执行查询:

mysql_query($sql);

http://php.net/manual/en/function.mysql-query.php

#3

you need to execute the query

你需要执行查询

Edit I added some lines in order to debug your query. Please copy & paste and tell me if you see any error.

编辑我添加了一些行以调试您的查询。如果您发现任何错误,请复制并粘贴并告诉我。

PIN:
E-Mail:

<?php
ini_set('display_startup_errors',1);
ini_set('display_errors',1);
error_reporting(-1);
if(isset($_POST["submit"])){

    if(!empty($_POST['pin']) && !empty($_POST['email'])) {
        $pin=$_POST['pin'];
        $email=$_POST['email'];

        $con=mysql_connect('localhost','root','admin') or die(mysql_error());
        mysql_select_db('user_codevalidation') or die("cannot select DB");

        $query=mysql_query("SELECT * FROM codes WHERE pin='".$pin."'");
        $numrows=mysql_num_rows($query);
        if($numrows!=0)
        {
            while($row=mysql_fetch_assoc($query))
            {
                $dbpin=$row['pin'];
            }

            if($pin == $dbpin)
            {
                $sql="INSERT INTO codes(email,claimed) VALUES('".$email."','1') WHERE pin = '".$dbpin."'";
                $res = mysql_query($sql) or die(mysql_error());
                echo "Successfully claimed!";
            }
        } else {
            echo "Invalid pin or it has already been claimed once!";
        }

    } else {
        echo "All fields are required!";
    }
}
?>

#1