C语言实现扫雷小游戏简单版

本文实例为大家分享了C语言实现扫雷小游戏的具体代码，供大家参考，具体内容如下

在vs2019创建新项目，然后添加两个源文件test.c和game.c，接着创建一个头文件game.h。

test.c:

#include "game.h"

void game()
{
 char mine[ROWS][COLS] = { 0 };
 char show[ROWS][COLS] = { 0 };

 InitBoard(mine, ROWS, COLS, '0');
 InitBoard(show, ROWS, COLS, '*');

 SetMine(mine, ROW, COL);

 //DispalyBoard(mine, ROW, COL);
 DispalyBoard(show, ROW, COL);

 FindMine(mine, show, ROW, COL);
}

void menu()
{
 printf("**************************\n");
 printf("******    1.play    ******\n");
 printf("******    0.exit    ******\n");
 printf("**************************\n");
}

int main()
{
 int input = 0;
 srand((unsigned int)time(NULL));
 do
 {
  menu();
  printf("请输入：");
  scanf("%d", &input);
  switch (input)
  {
  case 1:
   game();
   break;
  case 0:
   printf("退出游戏\n");
   break;
  default:
   printf("输入错误，请重新输入\n");
   break;
  }
 } while (input);
 return 0;
}

game.c:

#include "game.h"

void InitBoard(char board[ROWS][COLS], int rows, int cols, char set)
{
 int i = 0;
 for (i = 0; i < rows; i++)
 {
  int j = 0;
  for (j = 0; j < cols; j++)
  {
   board[i][j] = set;
  }
 }
}


void DispalyBoard(char board[ROWS][COLS], int row, int col)
{
 int i = 0;
 for (i = 0; i <= 9; i++)
 {
  printf("%d ", i);
 }
 printf("\n");
 for (i = 1; i <= row; i++)
 {
  int j = 0;
  printf("%d ", i);
  for (j = 1; j <= col; j++)
  {
   printf("%c ", board[i][j]);
  }
  printf("\n");
 }
}


void SetMine(char board[ROW][COL], int row, int col)
{
 int count = EASY_COUNT;
 while (count)
 {
  int x = rand() % row + 1;
  int y = rand() % col + 1;
  if (board[x][y] != '1')
  {
   board[x][y] = '1';
   count--;
  }
 }
}


int GetMineCount(char mine[ROWS][COLS], int x, int y)
{
 return (mine[x - 1][y] + mine[x - 1][y - 1] + mine[x][y - 1] + mine[x + 1][y - 1] +
  mine[x + 1][y] + mine[x + 1][y + 1] + mine[x][y + 1] + mine[x - 1][y + 1] - 8 * '0');
}

void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col)
{
 int x = 0;
 int y = 0;
 int win = 0;
 while (win<row*col-EASY_COUNT)
 {
  printf("请输入要排查的坐标：");
  scanf("%d%d", &x, &y);

  if (x >= 1 && x <= row && y >= 1 && y <= col)
  {
   if (mine[x][y] == '1')
   {
    printf("很遗憾，你被炸死了\n");
    DispalyBoard(mine, ROW, COL);
    break;
   }
   else
   {
    int count = GetMineCount(mine, x, y);
    show[x][y] = count + '0';
    DispalyBoard(show, ROW, COL);
    win++;
   }
  }
  else
  {
   printf("坐标非法，请重新输入\n");
  }
 }
 if (win == row * col - EASY_COUNT)
 {
  printf("排雷成功\n");
 }
}

game.h:

#pragma once

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define ROW 9
#define COL 9

#define EASY_COUNT 10
#define ROWS ROW+2
#define COLS COL+2
void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);
void DispalyBoard(char board[ROWS][COLS], int row, int col);
void SetMine(char board[ROWS][COLS], int row, int col);
void FindMine(char mine[ROW][COL], char show[ROW][COL], int row, int col);

运行效果如图：

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。

原文链接：https://blog.csdn.net/weixin_56667446/article/details/119186011