I'm not able to make ajax call to the controller action method which returns the json object. Also, I want to pass the integer-CheckID to the method.
我无法对返回json对象的控制器操作方法进行ajax调用。另外,我想将整数CheckID传递给方法。
Any help is highly appreciated. Thanks in Advance!
任何帮助都非常感谢。提前致谢!
***View***
<script type="text/javascript">
function showCheckImage(e) {
e.preventDefault();
var dataItem = this.dataItem($(e.currentTarget).closest("tr"));
var CheckID = dataItem.ID;
$.ajax({
url: '@Url.Action("GetDeferredCheckImage", "Customer")',
type: 'POST',
data: {deferredCheckID: CheckID },
dataType: 'json',
contentType: 'application/json; charset=utf-8',
success: function(result) {
//var imageObj = result;
alert('Loaded Image Object!');
},
error: function (result) {
alert('Error occurred while loading the image object.');
}
});
}
**Controller Method**
[HttpPost]
public JsonResult GetDeferredCheckImage(int deferredCheckID)
{
try
{
QCEventLogger.Log($"Gathering deferred check image for check ID: {deferredCheckID}", LogType.Default);
var response = new AjaxGetDeferredCheckImageViewModel(deferredCheckID);
QCEventLogger.Log($"Result of service call to gather deferred check image. check ID: {deferredCheckID}. Success: {response.Success}", LogType.Default);
var DeferredCheckImageObject = response.ImageCheckObject.DeferredCheckImages.FirstOrDefault();
return Json(DeferredCheckImageObject, JsonRequestBehavior.AllowGet);
}
catch (Exception ex)
{
var failureResponse = new AjaxGetDeferredCheckImageViewModel() { Success = false };
QCErrorLogger.Log($"Failure trying to gather deferred check image for check ID: {deferredCheckID}", ex);
return Json(failureResponse, JsonRequestBehavior.AllowGet);
}
}
1 个解决方案
#1
0
Your ajax call might be like this,
你的ajax调用可能是这样的,
$.ajax({
url: '@Url.Action("GetDeferredCheckImage", "Customer")',
type: 'POST',
data: { deferredCheckID: CheckID },
dataType: 'json',
success: function (result) {
//var imageObj = result;
alert('Loaded Image Object!');
},
error: function (result) {
alert('Error occurred while loading the image object.');
}
});
#1
0
Your ajax call might be like this,
你的ajax调用可能是这样的,
$.ajax({
url: '@Url.Action("GetDeferredCheckImage", "Customer")',
type: 'POST',
data: { deferredCheckID: CheckID },
dataType: 'json',
success: function (result) {
//var imageObj = result;
alert('Loaded Image Object!');
},
error: function (result) {
alert('Error occurred while loading the image object.');
}
});