方法一：使用列表推导式
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>>> vec = [[1,2,3],[4,5,6],[7,8,9]]
>>> get = [num for elem in vec for num in elem]
>>> get
[1, 2, 3, 4, 5, 6, 7, 8, 9]
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方法相当于
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>>> vec = [[1,2,3],[4,5,6],[7,8,9]]
>>> result = []
>>> for elem in vec:
for num in elem:
result.append(num)
>>> result
[1, 2, 3, 4, 5, 6, 7, 8, 9]
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方法二：
使用sum函数
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>>> vec = [[1,2,3],[4,5,6],[7,8,9]]
>>> get = sum(vec,[])
>>> get
[1, 2, 3, 4, 5, 6, 7, 8, 9]
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或者是使用chain函数
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>>> vec = [[1,2,3],[4,5,6],[7,8,9]]
>>> from itertools import chain
>>> list(chain(*vec))
[1, 2, 3, 4, 5, 6, 7, 8, 9]
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以上这篇python实现嵌套列表平铺的两种方法就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/guo_ridgepole/article/details/79953979