本文实例讲述了Python实现嵌套列表及字典并按某一元素去重复功能。分享给大家供大家参考，具体如下：
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#! /usr/bin/env python
#coding=utf-8
class HostScheduler(object):
def __init__(self, resource_list):
self.resource_list = resource_list
def MergeHost(self):
allResource=[]
allResource.append(self.resource_list[0])
for dict in self.resource_list:
#print len(l4)
k=0
for item in allResource:
#print 'item'
if dict['host'] != item['host']:
k=k+1
#continue
else:
break
if k == len(allResource):
allResource.append(dict)
taskhost=[]
for item in allResource:
taskhost.append(item['host'])
return taskhost
#该函数实现嵌套列表中，按某一元素去重复
def deleteRepeat():
#1、列表中嵌套列表。按元素‘b'实现去重复
l1=[['b',1],['b',2],['c',3],['a',1],['b',1],['b',1],]
l2=[]
l2.append(l1[0])
for data in l1:
#print len(l2)
k=0
for item in l2:
#print 'item'
if data[0] != item[0]:
k=k+1
else:
break
if k == len(l2):
l2.append(data)
print "l2: ",l2
#2、列表中嵌套字典。按键值host实现去重复
l3=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2},
{'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2},
{'host':'compute24', 'cpu':2}]
l4=[]
l4.append(l3[0])
for dict in l3:
#print len(l4)
k=0
for item in l4:
#print 'item'
if dict['host'] != item['host']:
k=k+1
#continue
else:
break
if k == len(l4):
l4.append(dict)
print "l4: ",l4
if __name__ == '__main__':
#deleteRepeat()
resource_list=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2},
{'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2},
{'host':'compute24', 'cpu':2}]
hostSchedule=HostScheduler(resource_list)
taskhost=hostSchedule.MergeHost()
print '服务器之家测试结果: '
print 'taskhost: '
print taskhost
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运行结果：
希望本文所述对大家Python程序设计有所帮助。
原文链接：http://blog.csdn.net/will130/article/details/50441937