本文实例讲述了Python实现对象转换为xml的方法。分享给大家供大家参考,具体如下:
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# -*- coding:UTF-8 -*-
'''''
Created on 2010-4-20
@author: 忧里修斯
'''
import xml.etree.ElementTree as ET
import xml.dom.minidom as minidom
from addrbook.domain import Person
class Converter( object ):
'''''
实现Python对象与xml之间的相互转换
'''
root = None #根节点
def __init__( self ):
pass
@staticmethod
def createRoot(rootTag):
'''''
创建根节点
'''
root = ET.Element(rootTag)
return root
@staticmethod
def getXmlString(element,defaultEncoding = 'utf-8' ):
'''''
根据节点返回格式化的xml字符串
'''
try :
rough_string = ET.tostring(element, defaultEncoding)
reparsed = minidom.parseString(rough_string)
return reparsed.toprettyxml(indent = " " , encoding = defaultEncoding)
except :
print 'getXmlString:传入的节点不能正确转换为xml,请检查传入的节点是否正确'
return ''
@staticmethod
def classToElements(classobj,rootTag = None ):
'''''
根据传入的对象的实例,根据对象的属性生成节点,返回由节点组成的列表
classobj:对象的实例
rootTag:根节点名称
'''
attrs = None #保存对象的属性集
elelist = [] #节点列表
try :
attrs = classobj.__dict__.keys() #获取该对象的所有属性(即成员变量)
except :
print 'classToElements:传入的对象非法,不能正确获取对象的属性'
if attrs ! = None and len (attrs) > 0 : #属性存在
for attr in attrs:
attrvalue = getattr (classobj, attr) #属性值
#属性节点
attrE = ET.Element(attr)
attrE.text = attrvalue
#加入节点列表
elelist.append(attrE)
return elelist
@staticmethod
def classToXML(classobj,rootTag = None ):
'''''
Python自定义模型类转换成xml,转换成功返回的是xml根节点,否则返回None
classobj:对象的实例
rootTag:根节点名称
'''
try :
classname = classobj.__class__.__name__ #类名
if rootTag ! = None :
root = Converter.createRoot(rootTag)
else :
root = Converter.createRoot(classname)
elelist = Converter.classToElements(classobj, rootTag)
for ele in elelist:
root.append(ele)
return root
except :
print 'classToXML:转换出错,请检查的传入的对象是否正确'
return None
@staticmethod
def collectionToXML(listobj,rootTag = 'list' ):
'''''
集合(列表、元组、字典)转换为xml,转换成功返回的是xml根节点,否则返回None
'''
try :
classname = listobj.__class__.__name__ #类名
root = Converter.createRoot(rootTag)
if isinstance (listobj, list ) or isinstance (listobj, tuple ): #列表或元组
if len (listobj) > = 0 :
for obj in listobj: #迭代列表中的对象
itemE = Converter.classToXML(obj)
root.append(itemE)
elif isinstance (listobj, dict ): #字典
if len (listobj) > = 0 :
for key in listobj: #迭代字典中的对象
obj = listobj[key]
itemE = Converter.classToXML(obj)
itemE. set ( 'key' , key)
root.append(itemE)
else :
print 'listToXML:转换错误,传入的对象:' + classname + '不是集合类型'
return root
except :
print 'collectionToXML:转换错误,集合转换成xml失败'
return None
if __name__ = = '__main__' :
p1 = Person( 'dredfsam' , '男' , '133665' )
p2 = Person( 'dream' , '女' , 'r' )
p3 = Person( '得分' , '男' , 'sdf' )
personList = {}
personList[ 'p1' ] = p1
personList[ 'p2' ] = p2
personList[ 'p3' ] = p3
# personList.append(p1)
# personList.append(p2)
# personList.append(p3)
root = Converter.collectionToXML(personList)
print Converter.getXmlString(root)
# plist = (p1,p2,p3)#{'name':'sdf'}
# print type(plist)
# print type(plist),isinstance(plist, list)
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希望本文所述对大家Python程序设计有所帮助。