采用二维数组制作五子棋，用坐标下棋。
请看代码。
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include<stdio.h>
#include<string.h>
#include<stdlib.h>
#include<windows.h>
#include<conio.h>
#include<time.h>
void menu()//目录
{
char xuanze = 0,xuanze2;
printf("\n");
printf("\n");
printf(" #############################################\n");
printf(" *五子棋小游戏*\n");
printf(" *1.双人游戏*\n");
printf(" *2.人机对战（暂未开放）\n");
printf(" *3.游戏须知\n");
printf(" #############################################\n");
printf(" 请选择选项，目前仅有 1 选项\n");
printf("\n");
printf(" ");
xuanze = _getch();
switch (xuanze)
{
case 1:
break;
case 3:
printf("本游戏是键盘输入坐标来落子的，白棋先落，第二次落子为黑色，依次落子。\n");
printf("若落子坐标非法则需重新落子。\n");
printf("键盘输入1直接进入游戏\n");
}
}
int t = 2;
int pan[20][20] =
{
{1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{4,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,5,6},
{7,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,8,9}
};
void qp()//棋盘
{
int i, j, k = 0;
printf(" ");
for (i = 0; i < 10; i++)
printf(" %d", i + 1);
for (i = 10; i < 20; i++)
printf("%d", i + 1);
printf("\n");
printf("1 ");
//printf("┌ ┬ ┐├ ┼ ┤└ ┴ ┘│ ");©○●┼
for (i = 0; i < 20; i++)
for (j = 0; j < 20; j++)
{
switch (pan[i][j])
{
case 1:
printf("┌ ");
k++;
if (k % 20 == 0)
{
printf("\n");
}
break;
case 2:
printf("┬ ");
k++;
if (k % 20 == 0)
printf("\n");
break;
case 3:
printf("┐ ");
k++;
if (k % 20 == 0)
{
printf("%d", i+1);
printf("\n");
printf("%d ", i + 1);
}
break;
case 4:
printf("├ ");
k++;
if (k % 20 == 0)
printf("\n");
break;
case 5:
printf("┼ ");
k++;
if (k % 20 == 0)
printf("\n");
break;
case 6:
printf("┤ ");
k++;
if (k % 20 == 0)
{
printf("%d", i+1);
printf("\n");
if(i<8)
printf("%d ", i + 2);
if(i>7)
printf("%d", i + 2);
}
break;
case 7:
printf("└ ");
k++;
if (k % 20 == 0)
printf("\n");
break;
case 8:
printf("┴ ");
k++;
if (k % 20 == 0)
printf("\n");
break;
case 9:
printf("┘ ");
k++;
if (k % 20 == 0)
{
printf("%d", i + 1);
printf("\n");
}
break;
case 10:
printf("○");
k++;
if (k % 20 == 0)
{
printf("%d", i+1);
printf("\n");
}
break;
case 11:
printf("●");
k++;
if (k % 20 == 0)
{
printf("%d", i+1);
printf("\n");
}
break;
}
}
printf(" ");
for (i = 0; i < 10; i++)
printf(" %d", i + 1);
for (i = 10; i < 20; i++)
printf("%d", i + 1);
printf("\n");
printf("\n");
}
void play()
{
int i, j;
while (1)
{
printf("*请选择落子坐标(x,y): ");
scanf_s("%d %d", &j, &i);
printf("\n");
if(i>0&&i<21&&j>0&&j<21)
{
if (pan[i - 1][j - 1] != 10 && pan[i - 1][j - 1] != 11)
{
if (t % 2 == 1)
{
t++;
pan[i - 1][j - 1] = 11;
break;
}
else if (t % 2 == 0)
{
t++;
pan[i - 1][j - 1] = 10;
break;
}
}
else if (pan[i-1][j-1] == 10 || pan[i-1][j-1] == 11)
{
printf("此处已经有棋子，请重新输入\n");
continue;
}
}
else if (i < 1 || i > 21 || j < 1 || j > 21)
{
printf("坐标不合法，请重新输入\n");
continue;
}
}
}
void test()
{
int i, j;
for(i=0;i<20;i++)
for (j = 0; j < 20; j++)
{
if (pan[i][j] != 1 || 2 || 3 || 4 || 5 || 6 || 7 || 8 || 9)
{
if (pan[i][j] == pan[i][j + 1]&&pan[i][j] == pan[i][j + 2]&&pan[i][j] == pan[i][j + 3]&&pan[i][j] == pan[i][j + 4])
{
if (pan[i][j] == 11)
{
printf("白棋获胜\n");
}
if (pan[i][j] == 10)
{
printf("黑棋获胜\n");
}
}
if (pan[i][j] == pan[i + 1][j]&&pan[i][j] == pan[i + 2][j]&&pan[i][j] == pan[i + 3][j]&&pan[i][j] == pan[i + 4][j])
{
if (pan[i][j] == 11)
{
printf("白棋获胜\n");
}
if (pan[i][j] == 10)
{
printf("黑棋获胜\n");
}
}
if (pan[i][j] == pan[i + 1][j + 1]&&pan[i][j] == pan[i + 2][j + 2]&&pan[i][j] == pan[i + 3][j + 3] &&pan[i][j]== pan[i + 4][j + 4])
{
if (pan[i][j] == 11)
{
printf("白棋获胜\n");
}
if (pan[i][j] == 10)
{
printf("黑棋获胜\n");
}
}
if (pan[i][j] == pan[i - 1][j + 1]&&pan[i][j] == pan[i - 2][j + 2] &&pan[i][j]== pan[i - 3][j + 3]&&pan[i][j] == pan[i - 4][j + 4])
{
if (pan[i][j] == 11)
{
printf("白棋获胜\n");
}
if (pan[i][j] == 10)
{
printf("黑棋获胜\n");
}
}
}
}
}
int main()
{
system("mode con cols=98 lines=48");
SetConsoleTitleA("五子棋小游戏"); //设置窗口
menu();
system("cls");
while (1)
{
qp();
test();
play();
system("cls");
}
system("pause");
return 0;
}
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原文链接：https://blog.csdn.net/may10/article/details/109448197