ASP.net实现页面跳转的方法

主要是使用response的属性，代码如下：

复制代码代码如下:

protected void LinkButton1_Click(object sender, EventArgs e) 
        { 
            string url = "InfoShow.aspx"; 
            Response.Redirect(url); 
        }

 

protected void LinkButton1_Click(object sender, EventArgs e)
        {
            string url = "InfoShow.aspx";
            Response.Redirect(url);
        }//当然我们可以在页面跳转的时候进行参数传递，代码如下：

protected void Menu1_MenuItemClick(object sender, MenuEventArgs e) 
       { 
           string url, s; 
           s = e.Item.Value.ToString(); 
           url = "InfoRelease.aspx?UserName=" + s.Trim(); 
           Response.Redirect(url); 
       }

 protected void Menu1_MenuItemClick(object sender, MenuEventArgs e)
        {
            string url, s;
            s = e.Item.Value.ToString();
            url = "InfoRelease.aspx?UserName=" + s.Trim();
            Response.Redirect(url);
        }

 
上面是我的一个项目中的代码所以有item，大家可以根据自己的情况进行设定。

 

那么既然传递了参数，在跳转的页面怎样获取呢？？？

代码如下：

 

复制代码代码如下:

protected void Page_Load(object sender, EventArgs e) 
       { 
           if (Request["UserName"] != null) 
           { 
               string s = Request["UserName"].ToString(); 
    //           form1.Visible = true; 
               txtInfoclass.Text = s; 
           } 
       }

 

 protected void Page_Load(object sender, EventArgs e)
        {
            if (Request["UserName"] != null)
            {
                string s = Request["UserName"].ToString();
     //           form1.Visible = true;
                txtInfoclass.Text = s;
            }
        }

 

 

复制代码代码如下:

protected void Page_Load(object sender, EventArgs e) 
       { 
           txtAlert.Text = ""; 
           if (Request["UserName"] != null) 
           { 
               string s = Request["UserName"].ToString(); 
    //           form1.Visible = true; 
               txtInfoclass.Text = s; 
           } 
       }

 

 protected void Page_Load(object sender, EventArgs e)
        {
            txtAlert.Text = "";
            if (Request["UserName"] != null)
            {
                string s = Request["UserName"].ToString();
     //           form1.Visible = true;
                txtInfoclass.Text = s;
            }
        }