用python语言来判断一个字符是否连续出现四次

Here's a piece of Python code that tells me if any character in a string occurs four times in a row:

下面是一段Python代码，它告诉我字符串中的任何字符是否连续出现4次:

str = "hello!!!!"
for i in range(0, len(str)-3):
   if str[i] == str[i+1] == str[i+2] == str[i+3]:
       print("yes")

What's a more Pythonic way of writing this, preferably with a regular expression?

什么是更python的写法，最好是正则表达式?

I'm aware of this similar question but it asks about a specific character, not any character.

我知道这个类似的问题，但它问的是一个特定的角色，而不是任何角色。

Number of the same characters in a row - python

行python中相同字符的数目

@JBernardo has an answer with regular expressions but it wants a particular character to match against.

@JBernardo有一个正则表达式的答案，但它想要一个特定的字符与之匹配。

I'm using Python 3, if it matters in your answer.

我用的是python3，如果它对你的答案有影响的话。

1 个解决方案

#1

Using regex you can use this to find a char that is repeated at least 4 times:

使用regex，您可以使用它查找至少重复4次的char:

>>> s = 'hello!!!!'

>>> print re.findall(r'(.)\1{3}', s)
['!']

Explanation:

解释:

• (.) - match any character and capture it as group #1
• 匹配任何字符并将其捕获为组1
• \1{3} - \1 is back-reference of captured group #1. \1{3} matches 3 instances of the captured character, this making it 4 repeats.
• \1{3} - \1是捕获的组#1的反向引用。\1{3}匹配捕获字符的3个实例，这使它重复4次。