Here is my input @Name as "Rupesh's"
这是我的输入@Name为"Rupesh "
I want to find 'Rupesh's' like name from the table 'AppliedPolicies
' table
我想从“应用策略”表中找到“Rupesh”的名字。
Select PolicyID, CustomerName, PolicyDesc
From AppliedPolicies
Where PolicyDesc = @Name
Plz. suggest me how could i get the required result.
请。建议我怎样才能得到要求的结果。
5 个解决方案
#1
3
Try this
试试这个
Select PolicyID, CustomerName, PolicyDesc
From AppliedPolicies
Where PolicyDesc like '%' + @Name + '%'
#2
1
Select PolicyID, CustomerName, PolicyDesc From AppliedPolicies
Where PolicyDesc like'%Rupesh'
for more http://www.w3schools.com/sql/sql_like.asp
更多的http://www.w3schools.com/sql/sql_like.asp
#3
1
You need to add another single quote to escape the single quote in the name, i.e. 'Rupesh''s'
您需要添加另一个单引号以避免名称中的单引号,即。“Rupesh“s”
Example:
例子:
declare @name varchar(20) = 'Rupesh''s'
SELECT * FROM
AppliedPolicies
WHERE PolicyDesc = @Name
#4
0
According to your title, maybe try this:
根据你的头衔,试试这个:
Select
PolicyID,
CustomerName,
PolicyDesc
From
AppliedPolicies
Where
PolicyDesc like '%''%'
#5
0
Try this SQL
试试这个SQL
Select PolicyID, CustomerName, PolicyDesc
From AppliedPolicies
Where Replace(PolicyDesc,'''','_') = Replace(**@Name**,'''','_')
#1
3
Try this
试试这个
Select PolicyID, CustomerName, PolicyDesc
From AppliedPolicies
Where PolicyDesc like '%' + @Name + '%'
#2
1
Select PolicyID, CustomerName, PolicyDesc From AppliedPolicies
Where PolicyDesc like'%Rupesh'
for more http://www.w3schools.com/sql/sql_like.asp
更多的http://www.w3schools.com/sql/sql_like.asp
#3
1
You need to add another single quote to escape the single quote in the name, i.e. 'Rupesh''s'
您需要添加另一个单引号以避免名称中的单引号,即。“Rupesh“s”
Example:
例子:
declare @name varchar(20) = 'Rupesh''s'
SELECT * FROM
AppliedPolicies
WHERE PolicyDesc = @Name
#4
0
According to your title, maybe try this:
根据你的头衔,试试这个:
Select
PolicyID,
CustomerName,
PolicyDesc
From
AppliedPolicies
Where
PolicyDesc like '%''%'
#5
0
Try this SQL
试试这个SQL
Select PolicyID, CustomerName, PolicyDesc
From AppliedPolicies
Where Replace(PolicyDesc,'''','_') = Replace(**@Name**,'''','_')