I have a string
我有一个字符串
"yes 12 /12 /yes /n
yes 12 /12 /yes "
How do I check that whenever I have "yes" in the string, I have a corresponding "/yes" and similarly, whenever I have "12", I have a corresponding "/12"? For example, if the string as
如果字符串中的“是”,我怎么检查,我有一个相应的“/ yes”,同样,只要我有“12”,我就有一个相应的“/ 12”?例如,如果字符串为
"yes 12 /12 /yes /n
yes 12 /12 "
It should give me an error saying error in line 2, and then move on reading the rest of the file.
它应该在第2行给出错误说错误,然后继续读取文件的其余部分。
4 个解决方案
#1
0
First you need to get a list of all words. Then for each word, try to see if /word is contained.
首先,您需要获取所有单词的列表。然后对于每个单词,尝试查看是否包含/ word。
String s = "12 a /12";
List<String> list = Arrays.asList(s.split("\\s"));
for (String value : list) {
if (list.contains("/" + value)) {
System.out.println("Does contain");
} else {
System.out.println("Doesn't contain");
}
}
#2
#3
0
use String.contains()
method
使用String.contains()方法
String s= "yes 12 /12 /yes /n"
if(s.contains("yes") && s.contains("/yes")){
sysout("yes");
}
do the same thing for any other pair :)
对任何其他对做同样的事情:)
#4
0
You can use some recursion to find the tags and the corresponding closing tag:
您可以使用一些递归来查找标记和相应的结束标记:
public class TagMatching {
public static void main(String[] args) {
List<String> lines = Arrays.asList("yes 12 /12 /yes /n",
"yes 12 /12 /yes",
"yes 12 a b /12 /yes",
"yes 12 c /12 /yes");
for (String line : lines) {
boolean valid = validate(Arrays.asList(line.split(" ")));
System.out.println("valid = " + valid);
}
}
public static boolean validate(List<String> tags) {
if (tags.size() == 0) {
return true;
}
String first = tags.get(0);
String last = tags.get(tags.size() - 1);
if (last.equals("/" + first)) {
return validate(tags.subList(1, tags.size()-1));
}
return false;
}
}
#1
0
First you need to get a list of all words. Then for each word, try to see if /word is contained.
首先,您需要获取所有单词的列表。然后对于每个单词,尝试查看是否包含/ word。
String s = "12 a /12";
List<String> list = Arrays.asList(s.split("\\s"));
for (String value : list) {
if (list.contains("/" + value)) {
System.out.println("Does contain");
} else {
System.out.println("Doesn't contain");
}
}
#2
0
You can use contains
method in String
class:
您可以在String类中使用contains方法:
String str = ""yes 12 /12 /yes /n";
boolean isOk = str.contains("yes") && str.contains("/yes"); // isOk = true
str = "yes 12 /12 ";
isOk = str.contains("12") && str.contains("/12") // isOk = false
#3
0
use String.contains()
method
使用String.contains()方法
String s= "yes 12 /12 /yes /n"
if(s.contains("yes") && s.contains("/yes")){
sysout("yes");
}
do the same thing for any other pair :)
对任何其他对做同样的事情:)
#4
0
You can use some recursion to find the tags and the corresponding closing tag:
您可以使用一些递归来查找标记和相应的结束标记:
public class TagMatching {
public static void main(String[] args) {
List<String> lines = Arrays.asList("yes 12 /12 /yes /n",
"yes 12 /12 /yes",
"yes 12 a b /12 /yes",
"yes 12 c /12 /yes");
for (String line : lines) {
boolean valid = validate(Arrays.asList(line.split(" ")));
System.out.println("valid = " + valid);
}
}
public static boolean validate(List<String> tags) {
if (tags.size() == 0) {
return true;
}
String first = tags.get(0);
String last = tags.get(tags.size() - 1);
if (last.equals("/" + first)) {
return validate(tags.subList(1, tags.size()-1));
}
return false;
}
}