返回Json时格式化日期Date
第一步:创建CustomObjectMapper类
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/**
* 解决SpringMVC使用@ResponseBody返回json时,日期格式默认显示为时间戳的问题。需配合<mvc:message-converters>使用
*/
@Component ( "customObjectMapper" )
public class CustomObjectMapper extends ObjectMapper {
public CustomObjectMapper() {
CustomSerializerFactory factory = new CustomSerializerFactory();
factory.addGenericMapping(Date. class , new JsonSerializer<Date>() {
@Override
public void serialize(Date value, JsonGenerator jsonGenerator,
SerializerProvider provider) throws IOException, JsonProcessingException {
SimpleDateFormat sdf = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss" );
jsonGenerator.writeString(sdf.format(value));
}
});
this .setSerializerFactory(factory);
}
}
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第二步:配置如下:
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< mvc:annotation-driven >
< mvc:message-converters >
< bean class = "org.springframework.http.converter.json.MappingJacksonHttpMessageConverter" >
< property name = "objectMapper" ref = "customObjectMapper" ></ property >
</ bean >
</ mvc:message-converters >
</ mvc:annotation-driven >
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效果如下:
格式化前
格式化后
进阶:返回自定义格式日期
使用@ResponseBody时返回json字符串的日期格式。Date类型属性默认返回一个Long型的时间戳,怎样能够返回自定义的日期格式?
解决方案:目前有两种方式实现,
1、局部修改(网上较多,但不推荐);
继承Jackson的抽象类:JsonSerializer<T>,然后在javabean的属性getter()上添加注解@JsonSerialize即可实现。
代码如下:
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import java.io.IOException;
import java.text.SimpleDateFormat;
import java.util.Date;
import org.codehaus.jackson.JsonGenerator;
import org.codehaus.jackson.JsonProcessingException;
import org.codehaus.jackson.map.JsonSerializer;
import org.codehaus.jackson.map.SerializerProvider;
/**
* @description 自定义返回JSON 数据格中日期格式化处理
*/
public class CustomDateSerializer extends JsonSerializer<Date> {
@Override
public void serialize(Date value,
JsonGenerator jsonGenerator,
SerializerProvider provider)
throws IOException, JsonProcessingException {
SimpleDateFormat sdf = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss" );
jsonGenerator.writeString(sdf.format(value));
}
}
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使用方式:
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@JsonSerialize (using = CustomDateSerializer. class )
public Date getCreateDate() {
return createDate;
}
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2、全局修改(强烈推荐):
MappingJacksonHttpMessageConverter主要通过ObjectMapper来实现返回json字符串。这里我们继承该类,注册一个JsonSerializer<T>。然后在配置文件中注入自定义的ObjectMapper。
代码如下:
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import java.io.IOException;
import java.text.SimpleDateFormat;
import java.util.Date;
import org.codehaus.jackson.JsonGenerator;
import org.codehaus.jackson.JsonProcessingException;
import org.codehaus.jackson.map.JsonSerializer;
import org.codehaus.jackson.map.ObjectMapper;
import org.codehaus.jackson.map.SerializerProvider;
import org.codehaus.jackson.map.ser.CustomSerializerFactory;
/**
* @description 解决Date类型返回json格式为自定义格式
*/
public class CustomObjectMapper extends ObjectMapper {
public CustomObjectMapper(){
CustomSerializerFactory factory = new CustomSerializerFactory();
factory.addGenericMapping(Date. class , new JsonSerializer<Date>(){
@Override
public void serialize(Date value,
JsonGenerator jsonGenerator,
SerializerProvider provider)
throws IOException, JsonProcessingException {
SimpleDateFormat sdf = new SimpleDateFormat( "yyyy-MM-dd HH:mm:ss" );
jsonGenerator.writeString(sdf.format(value));
}
});
this .setSerializerFactory(factory);
}
}
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spring-servlet.xml中配置:
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< mvc:annotation-driven >
< mvc:message-converters >
< bean class = "org.springframework.http.converter.json.MappingJacksonHttpMessageConverter" >
< property name = "objectMapper" ref = "customObjectMapper" ></ property >
</ bean >
</ mvc:message-converters >
</ mvc:annotation-driven >
< bean id = "customObjectMapper" class = "com.pmc.dwa.common.custom.CustomObjectMapper" ></ bean >
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