第一个值作为PHP数组中的键

时间:2021-12-21 03:18:42

I have this array:

我有这个数组:

$arr = array(
    0 => array( 'id' => 1, 'animal' => 'dog', 'color' => 'red' ),
    1 => array( 'id' => 12, 'animal' => 'cat', 'color' => 'green' ),
    2 => array( 'id' => 37, 'animal' => 'lion', 'color' => 'blue' ),
);

and I want this output:

我想要这个输出:

$arr = array(
    1 => array( 'animal' => 'dog', 'color' => 'red' ),
    12 => array( 'animal' => 'cat', 'color' => 'green' ),
    37 => array( 'animal' => 'lion', 'color' => 'blue' ),
);

Any good idea instead of using php loops, etc ?
Any functions? like array_values or array_combine

任何好主意而不是使用PHP循环等?任何功能?比如array_values或array_combine

=================
Possible solution

=================可能的解决方案

$new = array();
foreach( $arr as $item ){
    $id = array_shift( $item );
    $new[$id] = $item;
}

2 个解决方案

#1


Requires PHP >= 5.5.0 and the id will still be in the nested arrays:

需要PHP> = 5.5.0且id仍将在嵌套数组中:

$result = array_column($arr, null, 'id');

#2


One can define a new array and loop through the main array, using array_shift to pop first element (the id field) and then make the remaining part, value for that index in new array:

可以定义一个新数组并循环遍历主数组,使用array_shift弹出第一个元素(id字段),然后在新数组中为该索引创建剩余部分值:

$new = array();
foreach( $arr as $item ){
    $id = array_shift( $item );
    $new[$id] = $item;
}

#1


Requires PHP >= 5.5.0 and the id will still be in the nested arrays:

需要PHP> = 5.5.0且id仍将在嵌套数组中:

$result = array_column($arr, null, 'id');

#2


One can define a new array and loop through the main array, using array_shift to pop first element (the id field) and then make the remaining part, value for that index in new array:

可以定义一个新数组并循环遍历主数组,使用array_shift弹出第一个元素(id字段),然后在新数组中为该索引创建剩余部分值:

$new = array();
foreach( $arr as $item ){
    $id = array_shift( $item );
    $new[$id] = $item;
}