I need some way of capturing the text between square brackets. So for example, the following string:
我需要某种方法来捕获方括号之间的文本。例如，下面的字符串:
[This] is a [test] string, [eat] my [shorts].
这是[测试]字符串，[吃]我的[短裤]。
Could be used to create the following array:
可用于创建以下数组:
Array (
[0] => [This]
[1] => [test]
[2] => [eat]
[3] => [shorts]
)
I have the following regex, /\[.*?\]/ but it only captures the first instance, so:
我有以下的regex， /\ *?但它只捕捉到第一个实例，所以:
Array ( [0] => [This] )
How can I get the output I need? Note that the square brackets are NEVER nested, so that's not a concern.
我怎样才能得到我需要的输出?注意，方括号从不嵌套，所以这并不重要。
1 个解决方案
#1
78
Matches all strings with brackets:
将所有字符串与括号匹配:
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[[^\]]*\]/", $text, $matches);
var_dump($matches[0]);
If You want strings without brackets:
如果你想要没有括号的字符串:
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[([^\]]*)\]/", $text, $matches);
var_dump($matches[1]);
Alternative, slower version of matching without brackets (using "*" instead of "[^]"):
选择,慢的版本匹配没有括号(用“*”代替“[^]”):
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[(.*?)\]/", $text, $matches);
var_dump($matches[1]);
#1
78
Matches all strings with brackets:
将所有字符串与括号匹配:
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[[^\]]*\]/", $text, $matches);
var_dump($matches[0]);
If You want strings without brackets:
如果你想要没有括号的字符串:
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[([^\]]*)\]/", $text, $matches);
var_dump($matches[1]);
Alternative, slower version of matching without brackets (using "*" instead of "[^]"):
选择,慢的版本匹配没有括号(用“*”代替“[^]”):
$text = '[This] is a [test] string, [eat] my [shorts].';
preg_match_all("/\[(.*?)\]/", $text, $matches);
var_dump($matches[1]);