如何在php中合并两个没有重复值的数组？

I have two arrays: 1. each object here is a row retrived from database.

我有两个数组：1。这里的每个对象都是从数据库中恢复的一行。

    array
      1 => 
        object(stdClass)[41]
          public 'id' => string '1' (length=1)
          public 'class_id' => string '25' (length=2)
          public 'section_id' => string '2' (length=1)
          public 'student_id' => string '1' (length=1)
          public 'date' => string '2011-11-27' (length=10)
          public 'attendance' => string 'present' (length=7)
2 => 
        object(stdClass)[41]
          public 'id' => string '1' (length=1)
          public 'class_id' => string '25' (length=2)
          public 'section_id' => string '2' (length=1)
          public 'student_id' => string '3' (length=1)
          public 'date' => string '2011-11-27' (length=10)
          public 'attendance' => string 'present' (length=7)

2. Another array is from my form and this looks like this.

2.另一个数组来自我的表单，看起来像这样。

array
  0 => 
    array
      'class_id' => string '25' (length=2)
      'section_id' => string '2' (length=1)
      'student_id' => int 1
      'date' => string '2011-11-27 00:00:00' (length=19)
      'attendance' => string 'present' (length=7)
  1 => 
    array
      'class_id' => string '25' (length=2)
      'section_id' => string '2' (length=1)
      'student_id' => int 2
      'date' => string '2011-11-27 00:00:00' (length=19)
      'attendance' => string 'present' (length=7)

Here what I want to do is:
- compare these two and check if key student_id and date are already on database or not.
- and from second array which is from form data, remove duplicate and insert into data.
The final result should be:

这里我想要做的是： - 比较这两个并检查关键student_id和日期是否已经在数据库中。 - 从表单数据的第二个数组中删除重复并插入数据。最终结果应该是：

array
  0 => 
    array
      'class_id' => string '25' (length=2)
      'section_id' => string '2' (length=1)
      'student_id' => int 2
      'date' => string '2011-11-27 00:00:00' (length=19)
      'attendance' => string 'present' (length=7)

3 个解决方案

#1

Try:

尝试：

$c = [array_merge][1]($a,$b);

var_dump([array_unique][1]($c));

Hope it helps

希望能帮助到你

#2

Complementing the DemoUser's anwer, by setting the flag SORT REGULAR as an argument has resolved my "conversion array to string" problem:

通过将标志SORT REGULAR设置为参数来补充DemoUser的anwer，解决了我的“转换数组到字符串”问题：

$c = array_merge($a,$b);

$d = array_unique($c, SORT_REGULAR);

var_dump($d);

#3

Since both your arrays (database and form) are NOT exactly same you cannot call array_merge or array_unique functions. You will need to iterate the database rows once and store in returned values in a separate key-value based array (Map). And then iterate through your form returned array and search the previously prepared array for the key and if found just remove that element from form returned array. Consider following code snippet for this:

由于您的数组（数据库和表单）都不完全相同，因此无法调用array_merge或array_unique函数。您将需要迭代数据库行一次，并将返回值存储在单独的基于键值的数组（Map）中。然后遍历表单返回的数组并搜索先前准备好的数组中的键，如果找到则从表单返回的数组中删除该元素。请考虑以下代码段：

// assuming database returned rows are in $rows array
// assuming form returned records are in $forms array

$dbArray = array();
foreach($rows as $r) {
   // need to convert string to int and string to date to match data in both sets
   $dbArray[ array( (int) $r->student_id, strtotime($r->date) ) ] = 1;
}

$diffArray = array();
foreach($forms as $f) {
   $key = array( $f['student_id'], strtotime($f['date']) );
   if (!array_key_exists($key, $dbArray))
      $diffArray[] = $f;
}

// now $diffArray will have the final result you're looking for

#1