I have a string like
我有一根像绳子的
abc123/xyz456/abc/123/aaa/zzz
I would like to split it as
我想把它分成两份
abc123, xyz456 and abc/123/aaa/zzz
Basically, I want to split and get the first 2 items as separate items and the rest of the items can be combined.
基本上，我想将前两项分割为两个单独的项，其余的项可以合并。
I tried the regex ^(.*)\/(.*)\/(.*)$ but it gives me the other way around like zzz, aaa and abc123/xyz456/abc/123.
我试着regex ^(. *)\ / \ /(. *),(. *)美元但是我反过来喜欢打鼾声,aaa和abc123 / xyz456 / abc / 123。
Is there a way to get this parsed from left to right instead of right to left? or any suggestions would be helpful
有没有一种方法可以从左到右而不是从右到左进行解析?或者任何建议都是有益的。
2 个解决方案
#1
2
The easiest fix will be to modify the first two .* to .*? to make the first two .* lazy (that is, match up to the first occurrence of the subsequent subpattern):
最简单的解决方法是修改前两个。*?懒(即匹配后续子模式的第一次出现):
^(.*?)\/(.*?)\/(.*)$
^^^^^^^^^^^
See the regex demo
看到regex演示
Else, use negated character class [^\/] that matches any char but /:
别的,使用否定字符类[/ ^ \]匹配任何字符但/:
^([^\/]*)\/([^\/]*)\/(.*)$
See another demo
看到另一个演示
Note that * quantifier matches zero or more occurrences of the quantified subpattern, you need to replace it with + (one or more occurrences) if you need to match at least one.
注意，* quantifier匹配零个或多个量化子模式，如果需要匹配至少一个，则需要用+(一个或多个)替换它。
Note that the last .* can remain as is, a greedy pattern, as it is at the pattern end and will match as many chars (other than line break chars) as possible, up to the string end. Turning it to .*? (i.e. .*?$) makes no sense as it will slow down matching.
注意，最后的。*可以保持为贪婪模式，因为它在模式结束处，并将匹配尽可能多的字符(除换行字符)，直到字符串结束。把它。* ?(例如，*?$)毫无意义，因为它会减慢匹配速度。
#2
0
Try the following:
试试以下:
^([^\/]+)\/([^\/]+)\/(.*)$
#1
2
The easiest fix will be to modify the first two .* to .*? to make the first two .* lazy (that is, match up to the first occurrence of the subsequent subpattern):
最简单的解决方法是修改前两个。*?懒(即匹配后续子模式的第一次出现):
^(.*?)\/(.*?)\/(.*)$
^^^^^^^^^^^
See the regex demo
看到regex演示
Else, use negated character class [^\/] that matches any char but /:
别的,使用否定字符类[/ ^ \]匹配任何字符但/:
^([^\/]*)\/([^\/]*)\/(.*)$
See another demo
看到另一个演示
Note that * quantifier matches zero or more occurrences of the quantified subpattern, you need to replace it with + (one or more occurrences) if you need to match at least one.
注意，* quantifier匹配零个或多个量化子模式，如果需要匹配至少一个，则需要用+(一个或多个)替换它。
Note that the last .* can remain as is, a greedy pattern, as it is at the pattern end and will match as many chars (other than line break chars) as possible, up to the string end. Turning it to .*? (i.e. .*?$) makes no sense as it will slow down matching.
注意，最后的。*可以保持为贪婪模式，因为它在模式结束处，并将匹配尽可能多的字符(除换行字符)，直到字符串结束。把它。* ?(例如，*?$)毫无意义，因为它会减慢匹配速度。
#2
0
Try the following:
试试以下:
^([^\/]+)\/([^\/]+)\/(.*)$