从ruby中的多维数组中删除数组

How would this get done? Assume I have the following

怎么做到这一点?假设我有以下内容

arr = [[test, 0, 0, 0], [apples, 0, 9, 8]]

I know I would do something like:

我知道我会这样做:

def delete_me(item)
    arr.each do |a|
        if a[0] == item
            #delete the array containing test
        end
    end
end

delete_me('test')

As far as I can see you can only do: a.remove() but that leaves me with a empty [],m I don't want that, I want it completely gone.

据我所知,你只能这样做:a.remove()但是我留下了一个空的[],我不想要那个,我希望它完全消失了。

4 个解决方案

#1

You can use delete_if and match the first term to your argument:

您可以使用delete_if并将第一个术语与您的参数匹配:

arr = [['test', 0, 0, 0], ['apples', 0, 9, 8]]

def delete_me(array, term)
  array.delete_if {|x, *_| x == term }
end

(I've included the array as an argument as well, as the execution context is not clear from your post).

(我也把数组作为参数包含在内,因为你的帖子中的执行上下文不清楚)。

#2

Following up on @iamnotmaynard's suggestion:

跟进@ iamnotmaynard的建议:

arr.delete_if { |a| a[0] == 'test' }

#3

assoc.

arr.delete(arr.assoc("test"))

#4

I had a similar need to remove one or more columns that matched a text pattern.

我有类似的需要删除一个或多个匹配文本模式的列。

col_to_delete = 'test'
arr = [['test','apples','pears'],[2,3,5],[3,6,8],[1,3,1]]
arr.transpose.collect{|a| a if (a[0] != col_to_delete)}.reject(&:nil?).transpose
=> [["apples", "pears"], [3, 5], [6, 8], [3, 1]]

#1