如何获得多维数组的宽度和高度?

I have an array defined:

我定义了一个数组:

int [,] ary;
// ...
int nArea = ary.Length; // x*y or total area

This is all well and good, but I need to know how wide this array is in the x and y dimensions individually. Namely, ary.Length might return 12 - but does that mean the array is 4 high and 3 wide, or 6 high and 2 wide?

这很好，但是我需要知道这个数组在x和y维上的宽度。也就是说,必要。长度可能返回12——但这是否意味着数组是4高3宽，还是6高2宽?

How can I retrieve this information?

我如何检索这些信息?

5 个解决方案

#1

156

You use Array.GetLength with the index of the dimension you wish to retrieve.

你使用数组。GetLength与您希望检索的维度的索引。

#2

Use GetLength(), rather than Length.

使用GetLength()而不是Length。

int rowsOrHeight = ary.GetLength(0);
int colsOrWidth = ary.GetLength(1);

#3

// Two-dimensional GetLength example.
int[,] two = new int[5, 10];
Console.WriteLine(two.GetLength(0)); // Writes 5
Console.WriteLine(two.GetLength(1)); // Writes 10

#4

ary.GetLength(0) 
ary.GetLength(1)

for 2 dimensional array

2维数组

#5

Some of the other posts are confused about which dimension is which. Here's an NUNIT test that shows how 2D arrays work in C#

其他一些帖子对哪个维度是哪个维度感到困惑。这里有一个NUNIT测试，展示了2D数组在c#中的工作方式

[Test]
public void ArraysAreRowMajor()
{
    var myArray = new int[2,3]
        {
            {1, 2, 3},
            {4, 5, 6}
        };

    int rows = myArray.GetLength(0);
    int columns = myArray.GetLength(1);
    Assert.AreEqual(2,rows);
    Assert.AreEqual(3,columns);
    Assert.AreEqual(1,myArray[0,0]);
    Assert.AreEqual(2,myArray[0,1]);
    Assert.AreEqual(3,myArray[0,2]);
    Assert.AreEqual(4,myArray[1,0]);
    Assert.AreEqual(5,myArray[1,1]);
    Assert.AreEqual(6,myArray[1,2]);
}

#1

156