如何转置一个多维数组?

时间:2022-12-02 21:25:16

I think this might be a pretty simple question, but I haven't been able to figure it out yet. If I've got a 2-dimensional array like so:

我想这可能是一个很简单的问题,但我还没弄明白。如果我有一个二维数组

int[,] matris = new int[5, 8] { 
       { 1, 2, 3, 4, 5,6,7,8 }, 
       {9,10,11,12,13,14,15,16},
       { 17,18,19,20,21,22,23,24 },
       { 25,26,27,28,29,30,31,32 },
       { 33,34,35,36,37,38,39,40 },

        };

and a for loop, like this:

一个for循环,像这样

  for (int r = 0; r < 5; r++)
        {

            for (int j = 0; j < 8; j++)
                Console.Write("{0} ", matris[r, j]);

            Console.WriteLine();
        }

So with this code I am printing out the multi dimensional array. But how do I print out a transpose of the array?

我用这段代码打印出多维数组。但是我怎么打印出矩阵的a转置呢?

2 个解决方案

#1


17  

Just change your loops with each other:

只要互相改变你的循环:

for (int j = 0; j < 8; j++)
{
    for (int r = 0; r < 5; r++)
        Console.Write("{0} ", matris[r, j]);

    Console.WriteLine();
}

Creating new array:

创建新数组:

var newArray = new int[8, 5];
for (int j = 0; j < 8; j++)
    for (int r = 0; r < 5; r++)
        newArray[j, r] = matris[r, j];

#2


9  

You just need to do this:

你只需要这样做:

for (int r = 0; r < 8; r++)
{
    for (int j = 0; j < 5; j++)
        Console.Write("{0} ", matris[j, r]);
    Console.WriteLine();
}

#1


17  

Just change your loops with each other:

只要互相改变你的循环:

for (int j = 0; j < 8; j++)
{
    for (int r = 0; r < 5; r++)
        Console.Write("{0} ", matris[r, j]);

    Console.WriteLine();
}

Creating new array:

创建新数组:

var newArray = new int[8, 5];
for (int j = 0; j < 8; j++)
    for (int r = 0; r < 5; r++)
        newArray[j, r] = matris[r, j];

#2


9  

You just need to do this:

你只需要这样做:

for (int r = 0; r < 8; r++)
{
    for (int j = 0; j < 5; j++)
        Console.Write("{0} ", matris[j, r]);
    Console.WriteLine();
}