It's easier to show the code, than talk about it. I also searched the inter-webs for an answer, but could not find any, so here's my code:
展示代码比谈论它更容易。我也在互联网上寻找答案,但是没有找到,所以我的代码是:
http://pastebin.com/M606mXzR
I also added an output, which is on lines 50-70. Output from 61-70 is the "right" one, the one I want.
我还添加了一个输出,在第50-70行。61-70的输出是“正确”的,我想要的。
Am I using fill() method wrong, or what? Can't wrap my head around this...
我使用fill()方法是错误的,还是什么?我想不起来……
Is there really a difference?
真的有区别吗?
ClassB[][] classB_2Array = new ClassB[10][10];
Between this:
间:
for (ClassB[] classB_1Array : classB_2Array) {
Arrays.fill(classB_1Array, new ClassB());
}
to this:
:
for (int i = 0; i < classB_2Array.length; i++) {
for (int j = 0; j < classB_2Array[0].length; j++) {
classB_2Array[i][j] = new ClassB();
}
}
Anyways, just check out my code and thank you all for your answers!
不管怎样,只要看看我的代码,谢谢你们的回答!
1 个解决方案
#1
4
Answer to your question: Yes, there is a difference (see JavaDoc).
回答你的问题:是的,有区别(参见JavaDoc)。
Your first version puts one object instance into every single array element of a row. So a change to this instance is visible in every element in the same row of the array. You'll have i
ClassB
instances in total.
您的第一个版本将一个对象实例放入一行的每个数组元素中。因此,对这个实例的更改在数组的同一行中的每个元素中都是可见的。你总共有b类实例。
The second version puts its own instance into each array element. You'll have i*j
ClassB
instances in total.
第二个版本将自己的实例放入每个数组元素中。您将总共拥有i*j类b实例。
Your first version of the code is equivalent to
您的第一个版本的代码是等效的。
for (ClassB[] classB_1Array : classB_2Array) {
ClassB instance = new ClassB();
Arrays.fill(classB_1Array, instance);
}
Hope this information helps you, I did not look at your pastebin code.
希望这些信息对您有所帮助,我没有看您的pastebin代码。
EDIT:
编辑:
To clarify your misunderstanding, closely look at the output of this programm:
为了澄清您的误解,请仔细阅读本程序的输出:
import java.util.Arrays;
public class ArrayFiller {
public static void main(String[] args) {
// your first version:
Person[][] yourFirstVersion = new Person[2][2];
for (Person[] array : yourFirstVersion) {
Arrays.fill(array, new Person("Mike"));
}
System.out.println(Arrays.deepToString(yourFirstVersion));
yourFirstVersion[0][1].setName("Paul");
System.out.println(Arrays.deepToString(yourFirstVersion));
System.out.println("-----");
// equivalent: my version:
Person[][] myVersion = new Person[2][2];
for (Person[] array : myVersion) {
Person person = new Person("John");
Arrays.fill(array, person);
}
System.out.println(Arrays.deepToString(myVersion));
myVersion[0][1].setName("Thomas");
System.out.println(Arrays.deepToString(myVersion));
System.out.println("-----");
// your second version
Person[][] yourSecondVersion = new Person[2][2];
for (int i = 0; i < yourSecondVersion.length; i++) {
for (int j = 0; j < yourSecondVersion[i].length; j++) {
yourSecondVersion[i][j] = new Person("Max");
}
}
System.out.println(Arrays.deepToString(yourSecondVersion));
yourSecondVersion[0][1].setName("Chris");
System.out.println(Arrays.deepToString(yourSecondVersion));
}
private static class Person {
private String name;
public Person(String name) {
System.out.println("Constructor called for " + name);
this.name = name;
}
public void setName(String name) {
this.name = name;
}
@Override
public String toString() {
return name;
}
}
}
Here's the output:
输出:
Constructor called for Mike
Constructor called for Mike
[[Mike, Mike], [Mike, Mike]]
[[Paul, Paul], [Mike, Mike]]
-----
Constructor called for John
Constructor called for John
[[John, John], [John, John]]
[[Thomas, Thomas], [John, John]]
-----
Constructor called for Max
Constructor called for Max
Constructor called for Max
Constructor called for Max
[[Max, Max], [Max, Max]]
[[Max, Chris], [Max, Max]]
#1
4
Answer to your question: Yes, there is a difference (see JavaDoc).
回答你的问题:是的,有区别(参见JavaDoc)。
Your first version puts one object instance into every single array element of a row. So a change to this instance is visible in every element in the same row of the array. You'll have i
ClassB
instances in total.
您的第一个版本将一个对象实例放入一行的每个数组元素中。因此,对这个实例的更改在数组的同一行中的每个元素中都是可见的。你总共有b类实例。
The second version puts its own instance into each array element. You'll have i*j
ClassB
instances in total.
第二个版本将自己的实例放入每个数组元素中。您将总共拥有i*j类b实例。
Your first version of the code is equivalent to
您的第一个版本的代码是等效的。
for (ClassB[] classB_1Array : classB_2Array) {
ClassB instance = new ClassB();
Arrays.fill(classB_1Array, instance);
}
Hope this information helps you, I did not look at your pastebin code.
希望这些信息对您有所帮助,我没有看您的pastebin代码。
EDIT:
编辑:
To clarify your misunderstanding, closely look at the output of this programm:
为了澄清您的误解,请仔细阅读本程序的输出:
import java.util.Arrays;
public class ArrayFiller {
public static void main(String[] args) {
// your first version:
Person[][] yourFirstVersion = new Person[2][2];
for (Person[] array : yourFirstVersion) {
Arrays.fill(array, new Person("Mike"));
}
System.out.println(Arrays.deepToString(yourFirstVersion));
yourFirstVersion[0][1].setName("Paul");
System.out.println(Arrays.deepToString(yourFirstVersion));
System.out.println("-----");
// equivalent: my version:
Person[][] myVersion = new Person[2][2];
for (Person[] array : myVersion) {
Person person = new Person("John");
Arrays.fill(array, person);
}
System.out.println(Arrays.deepToString(myVersion));
myVersion[0][1].setName("Thomas");
System.out.println(Arrays.deepToString(myVersion));
System.out.println("-----");
// your second version
Person[][] yourSecondVersion = new Person[2][2];
for (int i = 0; i < yourSecondVersion.length; i++) {
for (int j = 0; j < yourSecondVersion[i].length; j++) {
yourSecondVersion[i][j] = new Person("Max");
}
}
System.out.println(Arrays.deepToString(yourSecondVersion));
yourSecondVersion[0][1].setName("Chris");
System.out.println(Arrays.deepToString(yourSecondVersion));
}
private static class Person {
private String name;
public Person(String name) {
System.out.println("Constructor called for " + name);
this.name = name;
}
public void setName(String name) {
this.name = name;
}
@Override
public String toString() {
return name;
}
}
}
Here's the output:
输出:
Constructor called for Mike
Constructor called for Mike
[[Mike, Mike], [Mike, Mike]]
[[Paul, Paul], [Mike, Mike]]
-----
Constructor called for John
Constructor called for John
[[John, John], [John, John]]
[[Thomas, Thomas], [John, John]]
-----
Constructor called for Max
Constructor called for Max
Constructor called for Max
Constructor called for Max
[[Max, Max], [Max, Max]]
[[Max, Chris], [Max, Max]]