如何删除一个数组对象如果数组不是由一个ArrayList吗?(复制)

This question already has an answer here:

这个问题已经有了答案:

• How do I remove objects from an array in Java? 18 answers
• 如何删除对象在Java数组吗?18个答案
• Removing an element from an Array (Java) [duplicate] 15 answers
• 从数组中删除一个元素(Java)[复制]15个答案。

I am trying to remove a meteor in my game for when it his a bullet but there seems to be an error, and I do not now another method to remove the object.

我试图在我的游戏中移除一颗流星，因为它是一颗子弹，但似乎有一个错误，而我现在没有另一种方法来移除这个物体。

for (int i = 0; i < numA; i++) {
    if (meteor[i].isVisible())
      meteor[i].move();
    else meteor[i].remove(i);
    }

3 个解决方案

#1

You know, you should actually use a Set for that. An array is much too inefficient.

你知道,你应该使用一组。一个数组太低效了。

To do this, instead of declaring an array:

这样做，而不是声明一个数组:

private Meteor[] meteor = new Meteor[10];

declare a Set:

声明一组:

private Set<Meteor> meteor = new HashSet<Meteor>();

You can add meteors:

您可以添加流星:

meteor.add(newMeteor);

and remove them:

和删除:

meteor.remove(meteorToRemove);

and check if they are in the set:

检查它们是否在集合中:

if (meteor.contains(met))

and iterate through them:

和遍历:

for (Meteor m : meteor)

#2

Apache has a commons utility method in ArrayUtils that could help. It works like this:

Apache在ArrayUtils中有一个可以帮助的commons实用程序方法。是这样的:

array = ArrayUtils.removeElement(meteor, elementToDelete)

= ArrayUtils数组。elementToDelete removeElement(流星)

Check out the docs for more info: Apache Docs

更多信息查看文档:Apache文档

#3

array only solution

for (int i = 0; i < numA; i++) {
    if (meteor[i].isVisible())
        meteor[i].move();
    else {
        Meteor[] result = new Meteor[meteor.length - 1];
        System.arraycopy(meteor, 0, result, 0, i);
        if (meteor.length != i) {
            System.arraycopy(meteor, i + 1, result, i, meteor.length - i - 1);
        }
        meteor = result;
    }
}