I don't understand what the problem is with the code, it is very simple so this is an easy one.
我不明白代码有什么问题,它很简单,所以这很简单。
x = input("Give starting number: ")
y = input("Give ending number: ")
for i in range(x,y):
print(i)
It gives me an error
它给了我一个错误
Traceback (most recent call last):
File "C:/Python33/harj4.py", line 6, in <module>
for i in range(x,y):
TypeError: 'str' object cannot be interpreted as an integer
As an example, if x is 3 and y is 14, I want it to print
举个例子,如果x = 3 y = 14,我想打印出来
Give starting number: 4
Give ending number: 13
4
5
6
7
8
9
10
11
12
13
What is the problem?
这个问题是什么?
6 个解决方案
#1
8
A simplest fix would be:
最简单的解决办法是:
x = input("Give starting number: ")
y = input("Give ending number: ")
x = int(x) # parse string into an integer
y = int(y) # parse string into an integer
for i in range(x,y):
print(i)
input
returns you a string (raw_input
in Python 2). int
tries to parse it into an integer. This code will throw an exception if the string doesn't contain a valid integer string, so you'd probably want to refine it a bit using try
/except
statements.
输入返回字符串(Python 2中的raw_input)。int试图将其解析为整数。如果字符串不包含有效的整型字符串,那么该代码将抛出一个异常,因此您可能希望使用try/except语句对其进行一些细化。
#2
0
I'm guessing you're running python3, in which input(prompt)
returns a string. Try this.
我猜您在运行python3,输入(提示符)返回一个字符串。试试这个。
x=int(input('prompt'))
y=int(input('prompt'))
#3
0
You have to convert input x and y into int like below.
你必须将输入x和y转换成如下的整数。
x=int(x)
y=int(y)
#4
0
You will have to put:
你必须写:
X = input("give starting number")
X = int(X)
Y = input("give ending number")
Y = int(Y)
#5
0
Or you can also use eval(input('prompt'))
.
或者也可以使用eval(input('prompt'))。
#6
0
x = int(input("Give starting number: "))
y = int(input("Give ending number: "))
P.S. Add function int()
注:添加int()函数
#1
8
A simplest fix would be:
最简单的解决办法是:
x = input("Give starting number: ")
y = input("Give ending number: ")
x = int(x) # parse string into an integer
y = int(y) # parse string into an integer
for i in range(x,y):
print(i)
input
returns you a string (raw_input
in Python 2). int
tries to parse it into an integer. This code will throw an exception if the string doesn't contain a valid integer string, so you'd probably want to refine it a bit using try
/except
statements.
输入返回字符串(Python 2中的raw_input)。int试图将其解析为整数。如果字符串不包含有效的整型字符串,那么该代码将抛出一个异常,因此您可能希望使用try/except语句对其进行一些细化。
#2
0
I'm guessing you're running python3, in which input(prompt)
returns a string. Try this.
我猜您在运行python3,输入(提示符)返回一个字符串。试试这个。
x=int(input('prompt'))
y=int(input('prompt'))
#3
0
You have to convert input x and y into int like below.
你必须将输入x和y转换成如下的整数。
x=int(x)
y=int(y)
#4
0
You will have to put:
你必须写:
X = input("give starting number")
X = int(X)
Y = input("give ending number")
Y = int(Y)
#5
0
Or you can also use eval(input('prompt'))
.
或者也可以使用eval(input('prompt'))。
#6
0
x = int(input("Give starting number: "))
y = int(input("Give ending number: "))
P.S. Add function int()
注:添加int()函数