I have 60 equations with 70 variables. all of them are in one list:
我有60个方程，有70个变量。所有这些都在一个列表中：
(x0,x1,...,x239) are sympy symbols
（x0，x1，...，x239）是同情符号
list_a = [Xor(Not(x40), Not(x86)), Xor(x41, Not(x87)), ...]
and my question is, if it is possible somehow transform this equations to matrix or solved them. I think, that it can have more than one solution.
而我的问题是，如果有可能以某种方式将这些方程转换为矩阵或解决它们。我认为，它可以有多个解决方案。
1 个解决方案
#1
1
A solution to a system of logic expressions is the same as checking SAT for the conjunction (And) of the expressions.
逻辑表达式系统的解决方案与检查SAT表达式的连接（And）相同。
In [3]: list_a = [Xor(Not(x40), Not(x86)), Xor(x41, Not(x87))]
In [4]: list_a
Out[4]: [¬x₄₀ ⊻ ¬x₈₆, x₄₁ ⊻ ¬x₈₇]
In [5]: satisfiable(And(*list_a))
Out[5]: {x87: False, x40: True, x86: False, x41: False}
If you want all solutions you can pass all_models=True, although note that in the general case there are exponentially many solutions.
如果您想要所有解决方案，您可以传递all_models = True，但请注意，在一般情况下，存在指数级的解决方案。
#1
1
A solution to a system of logic expressions is the same as checking SAT for the conjunction (And) of the expressions.
逻辑表达式系统的解决方案与检查SAT表达式的连接（And）相同。
In [3]: list_a = [Xor(Not(x40), Not(x86)), Xor(x41, Not(x87))]
In [4]: list_a
Out[4]: [¬x₄₀ ⊻ ¬x₈₆, x₄₁ ⊻ ¬x₈₇]
In [5]: satisfiable(And(*list_a))
Out[5]: {x87: False, x40: True, x86: False, x41: False}
If you want all solutions you can pass all_models=True, although note that in the general case there are exponentially many solutions.
如果您想要所有解决方案，您可以传递all_models = True，但请注意，在一般情况下，存在指数级的解决方案。